How to Handle the Distribution 1/(x-i0)^2?

ziojoe
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I have a little problem with the following exercise:
"Consider the temperate distribution

f\left(x\right)=\frac{1}{\left(x-i0\right)^2}

Write f(x) like function of elementary temperate distributions and calculate its Fourier-transform."
I am almost sure I have to use the identity

\frac{1}{x-i0}=PP\frac{1}{x}+i\pi\delta\left(x\right)

But the square makes appear terms like \delta^2\left(x\right), that is not a distribution.

Any idea?
 
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What is "the temperate distribution", and what is an "elementary temperate distribution"?

What is "i0"? E.g. is 0 simply an arbitrarily small positive number?

The original equation defines a function with one double pole (assuming my example interpretation of 0 above). I don't see any need to use distribution theory. You can evaluate the Fourier transform using the Cauchy Integral Theorem (assuming my example interpretation of 0 above).
 
turin said:
What is "the temperate distribution", and what is an "elementary temperate distribution"?

I think this means "tempered distribution" and "regular distribution that is also a tempered distribution."
turin said:
What is "i0"? E.g. is 0 simply an arbitrarily small positive number?

I think so. This is usually denoted x- i \epsilon.
turin said:
The original equation defines a function with one double pole (assuming my example interpretation of 0 above). I don't see any need to use distribution theory. You can evaluate the Fourier transform using the Cauchy Integral Theorem (assuming my example interpretation of 0 above).

But I think the idea behind the question is to gain familiarity with distribution theory.
ziojoe said:
Any idea?

\frac{1}{\left( x - i \epsilon \right)^2} = - \frac{d}{dx} \left[ \frac{1}{ x - i \epsilon} \right]
 
Thanks, that was exactly the answer I got myself after a while. Thanks again.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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