How to Integrate 1/sqrt(1+x^2) dx | Step-by-Step Solution

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The integral of 1/sqrt(1+x^2) dx can be solved using the substitution x = tan(t), leading to the integral transforming into tan^-1(x) + C. There is confusion regarding the appearance of sine in other solutions, which may stem from different approaches or identities used in integration. The discussion emphasizes the importance of correctly applying integration formulas and recognizing the relationship between trigonometric identities and inverse functions. Clarification is provided that the correct expression for the integral is arctan(x) + C, not arctan(t) + C. Understanding these nuances is crucial for accurate integration of special functions.
Mathematicsss

Homework Statement


Integral of 1/sqrt(1+x^2) dx

Homework Equations


sin^2theta`+cos^2theta=1
1+tan^2theta=sec^2theta

The Attempt at a Solution


I plugged x=tant --> dx=sec^2t dt
=> integral of 1/sqrt9(1+tan^2t) sec^2t dt
= integral of t = tan^-1t + C

However, another answer I've seen involves sin, why is that?
 
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Mathematicsss said:

Homework Statement


Integral of 1/sqrt(1+x^2) dx

Homework Equations


sin^2theta`+cos^2theta=1
1+tan^2theta=sec^2theta

The Attempt at a Solution


I plugged x=tant --> dx=sec^2t dt
=> integral of 1/sqrt9(1+tan^2t) sec^2t dt
= integral of t = tan^-1t + C

However, another answer I've seen involves sin, why is that?

Setting ##t = \arctan(t) + C## is wrong.
 
Ray Vickson said:
Setting ##t = \arctan(t) + C## is wrong.
I meant t=arctan(x)+C
 
Hello

This is a formula.
Check Integration Formulas - Integration of Special Functions, number 6
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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