How to Prove a Complex Inequality with Complex Algebra

AI Thread Summary
The discussion revolves around proving the inequality |1+ab| + |a+b| ≥ √(|a²-1||b²-1|) for complex numbers a and b. Participants suggest factoring the left-hand side and exploring the expression |(a-1)(a+1)(b-1)(b+1)| to find a solution. The approach includes rearranging and recombining factors to simplify the proof. There is a focus on utilizing properties of complex algebra to tackle the problem. Overall, the thread emphasizes collaborative problem-solving in complex inequalities.
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Homework Statement


Let b and a be two complex numbers. Prove that
|1+ab| + |a + b| ≥ √(|a²-1||b²-1|).

Homework Equations


Complex algebra

The Attempt at a Solution


I don't know how to proceed. I posted it here to get some ideas :p
 
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Try factoring the left hand side:
$$|a^2 - 1||b^2 - 1| = |(a-1)(a+1)(b-1)(b+1)|$$
Now see what happens if you rearrange the factors and recombine them.
 
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