How to prove that motion is periodic but not simple harmonic?

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The discussion focuses on proving that the function x = sin(ωt) + sin(2ωt) + sin(4ωt) is periodic but not simple harmonic motion (SHM). Participants analyze the individual components, noting that while each term represents SHM, their sum does not satisfy the condition where acceleration is proportional to displacement (a = -ω²x). They emphasize the importance of plotting the function to visually confirm periodicity and to demonstrate that it does not resemble a sinusoidal wave. The consensus is that the motion is periodic with a period T = 2π/ω, but the combined function does not fit the criteria for SHM. Ultimately, the function's non-sinusoidal nature confirms it is periodic but not simple harmonic.
vcsharp2003
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TL;DR Summary: Prove that a sum of trigonometric ratios is periodic but not not simple harmonic.

We need to prove that ##x = sin{\omega t} + sin{2\omega t} + sin{4\omega t}## where ##x## is the displacement from the equilibrium position at time ##t##.

I can see that each term is a SHM, but not sure if the sum of these terms would be a simple harmonic motion.
Also, I can see that the time period of third term is one-fourth that of first term and time period of second term is half that of first term.

But after the above analysis, I am confused.
 
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Is there a number I can add to t to get the same x? What if I add 2t? 3t?
 
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Addendum to the question posed by @Vanadium 50 above.
To complete the answer, you also have to prove that ##x## is periodic and find its period ##T##.
You might also wish to plot ##x## to guide your thinking.
 
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For SHM at angular frequency ##\Omega##, ##x## can always be expressed as ##x = A\sin(\Omega t + \phi)##.

So, for SHM, how is ##\ddot x## related to ##x##?
 
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It is interesting that the easiest way to do this problem is to graph it for interval τ such that ωτ~10 π. You will immediately see if it repeats and if it looks like a sinusoid. Then you can show the result analytically as required. A lesson well learned
 
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TSny said:
For SHM at angular frequency ##\Omega##, ##x## can always be expressed as ##x = A\sin(\Omega t + \phi)##.

So, for SHM, how is ##\ddot x## related to ##x##?
##a= -\omega ^2 x##
 
hutchphd said:
It is interesting that the easiest way to do this problem is to graph it for interval τ such that ωτ~10 π. You will immediately see if it repeats and if it looks like a sinusoid. Then you can show the result analytically as required. A lesson well learned
Did you mean ##\omega t = 10 \pi##?
 
vcsharp2003 said:
##a= -\omega ^2 x##
Or, ##\ddot x = -\Omega^2 x## for the example I gave.

The important thing is that for SHM the acceleration equals a constant times the displacement.

Does your series expression for ##x## have this property?
 
vcsharp2003 said:
Did you mean ωt=10π?
Did I say that awkwardly? The longest period T possible will be T=2π/ω so I want to look for times ~ five times that interval. Brain fog lately
 
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  • #10
hutchphd said:
Did I say that awkwardly?
You didn't use the equal sign, so I was confused.
 
  • #11
Brain fog. I could see the = sign!! Apologies
 
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  • #12
TSny said:
Or, ##\ddot x = -\Omega^2 x## for the example I gave.

The important thing is that for SHM the acceleration equals a constant times the displacement.

Does your series expression for ##x## have this property?
I get the following, after taking, second derivative of ##x## wrt ##t##.

##a= -\omega ^2 x -\omega ^2 (3 sin{(2\omega t)} + 15sin {(4\omega t)})##

Since for SHM, ##a= -\omega ^2 x##, so it's not SHM after looking at the above equation for ##a##. Is that correct reasoning?
 
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  • #13
Vanadium 50 said:
Is there a number I can add to t to get the same x? What if I add 2t? 3t?
I get the following, but I cannot see the value of ##x## repeating.

##x(t+2t) = sin3\omega t + sin6\omega t +sin12\omega t##

##x(t+3t) = sin4\omega t + sin8\omega t +sin16\omega t##
 
  • #14
vcsharp2003 said:
I get the following, after taking, second derivative of ##x## wrt ##t##.

##a= -\omega ^2 x + 3 sin{2\omega t} + 15sin {4\omega t}##
That looks like it needs some parenthesis?
 
  • #15
erobz said:
That looks like it needs some parenthesis?
You mean parenthesis around ##2\omega t## and ##4\omega t##?
 
  • #16
vcsharp2003 said:
You mean parenthesis around ##2\omega t## and ##4\omega t##?
I meant:

$$\ddot x = -\omega^2 ( x + 3 \sin ( 2\omega t )+15\sin ( 4\omega t ) )$$
 
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  • #17
erobz said:
I meant:

$$\ddot x = -\omega^2 ( x + 3 \sin ( 2\omega t )+15\sin ( 4\omega t ) )$$
Thanks! I couldn't parse what he posted... :smile:
 
  • #18
berkeman said:
Thanks! I couldn't parse what he posted... :smile:
Yes, my mistake. I had the following in my notebook, but wrote it incorrectly in the forums.

##a= -\omega ^2 x -\omega ^2 (3 sin{2\omega t} + 15sin {4\omega t})##

Also, I've corrected the equation in post#12 for which you reported the error.
 
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  • #19
vcsharp2003 said:
I get the following, but I cannot see the value of ##x## repeating.
Hint: Clearly ##x=0## at ##t=0##. At what value of ##t## does the next ##x=0## occur? How about the one after that?
 
  • #20
kuruman said:
Hint: Clearly ##x=0## at ##t=0##. At what value of ##t## does the next ##x=0## occur? How about the one after that?
That's not easy to me. Do I have to solve the trigonometric equation ##0=sin{\omega t} + sin{2\omega t} + sin{4\omega t}##?

It seems when ## t= \dfrac {\pi}{w}## then also ##x=0##.
 
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  • #21
vcsharp2003 said:
That's not easy to me. Do I have to solve the trigonometric equation ##0=sin{\omega t} + sin{2\omega t} + sin{4\omega t}##?
Not really. Take first term,##~\sin(\omega t)##. At what values of ##t## is it zero? Were you not taught that when you took trig?
 
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  • #22
vcsharp2003 said:
That's not easy to me. Do I have to solve the trigonometric equation ##0=sin{\omega t} + sin{2\omega t} + sin{4\omega t}##?
Further hint: think of certain multiples of a very famous transcendental number.
 
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  • #23
kuruman said:
Not really. Take first term,##~\sin(\omega t)##. At what values of ##t## is it zero? Were you not taught that when you took trig?
Yes, I can see it. First term would be zero when ##t = n\pi## where n is any integer i.e. +ve or -ve or zero.
 
  • #24
erobz said:
Further hint: think of certain multiples of a very famous transcendental number.
Hahaha. That's a nice hint.
 
  • #25
vcsharp2003 said:
It seems when ## t= \dfrac {\pi}{w}## then also ##x=0##.
So it seems. But are the two the same kind of zero in the sense that ##\sin(\omega t)## crosses the axis going the same way? That's why I suggested that you plot this thing.
 
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  • #26
kuruman said:
So it seems. But are the two the same kind of zero in the sense that ##\sin(\omega t)## crosses the axis going the same way? That's why I suggested that you plot this thing.
I see. I will try that too.
 
  • #27
vcsharp2003 said:
Hahaha. That's a nice hint.
Parity matters as @kuruman points out, which is why I said certain multiples.
 
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  • #28
kuruman said:
That's why I suggested that you plot this thing.
First thing I did. :wink: We often take for granted the tools we now have at our disposal to answer these types of questions with almost no effort. Then (once you know what you are working toward) worry about the mathematical purist approach!
 
  • #29
erobz said:
Parity matters as @kuruman points out, which is why I said certain multiples.
##n=0,1,2,3...##. Is this what you meant by certain multiples?
 
  • #30
vcsharp2003 said:
##n=0,1,2,3...##. Is this what you meant by certain multiples?
parity refers to even-odd
 
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