How to show an equation with n'th number of iterations

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The discussion focuses on deriving a mathematical expression for the velocity of the n'th object relative to the first observer, given a scenario where multiple objects are moving away at the same speed. The key equation used is g = (a+b) / (1+ab), where 'g' represents the velocity of the n'th object, 'a' is the previous object's velocity, and 'b' is the last object's velocity relative to the previous one. While the user successfully demonstrates the formula for small values of n, they struggle to generalize it for larger n. The conversation also touches on the concept of rapidities, which simplify the addition of velocities, but the user is uncertain about using them due to their unfamiliarity. Ultimately, the user finds a solution using rapidities, indicating progress in their understanding.
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Homework Statement


An observer measures an object moving away at speed v=0,75, an observer on that object measures another object moving away in the same direction with the same speed relative to it and this is repeated n times. Find the velocity of the n'th object relative to the first.

I didnt post in the physics section, as its just the maths that is the tricky part. Showing this formula for n objects, when each object relies on the same equation for the previous object etc.

Homework Equations


w = u+v / (1 + uv) derived from k calculus

The Attempt at a Solution


I have understand and have sorted out the physics in this, but am unsure of how to show the answer mathematically. For large n, g => 1.

g = (a+b) / (1+ab) , where g) is the velocity of the n'th object relative to the original observer.
b) is the velocity of the last (n'th) object relative to the previous, a) is the previous object velocity relative to the one before it, all the way back to the original.
In a few steps I keep subbing in this equation into it self, and while I can show it works for small n, It am unsure of how to show this mathematically for large n.
 
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I recall something like =(a+b)(1-ab+(ab)^2 - (ab)^3+...
 
vmr101 said:

Homework Statement


An observer measures an object moving away at speed v=0,75, an observer on that object measures another object moving away in the same direction with the same speed relative to it and this is repeated n times. Find the velocity of the n'th object relative to the first.

I didnt post in the physics section, as its just the maths that is the tricky part. Showing this formula for n objects, when each object relies on the same equation for the previous object etc.

Homework Equations


w = u+v / (1 + uv) derived from k calculus

The Attempt at a Solution


I have understand and have sorted out the physics in this, but am unsure of how to show the answer mathematically. For large n, g => 1.

g = (a+b) / (1+ab) , where g) is the velocity of the n'th object relative to the original observer.
b) is the velocity of the last (n'th) object relative to the previous, a) is the previous object velocity relative to the one before it, all the way back to the original.
In a few steps I keep subbing in this equation into it self, and while I can show it works for small n, It am unsure of how to show this mathematically for large n.

Look here http://en.wikipedia.org/wiki/Velocity-addition_formula at rapidities. Combining velocities gets complicated. Adding rapidities is easy, they just add. Give an expression using hyperbolic tangents.
 
I had a look at rapidities but we haven't gone through them so I don't think that's how they want us to show this.
Any other advice?
 
vmr101 said:
I had a look at rapidities but we haven't gone through them so I don't think that's how they want us to show this.
Any other advice?

I guess I don't know any other closed form to express the answer in. Rapidities are easy.
 
I read up on the rapidities and i can make it work :) Thanks Dick.
 
vmr101 said:
I read up on the rapidities and i can make it work :) Thanks Dick.

Good for you. I knew you'd like the solution when you figured it out.
 
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