latentcorpse Messages 1,411 Reaction score 0 Thread starter Apr 26, 2009 #1 if [itex]\epsilon_{ijk} P_{kj}=0[/itex] how do we show [itex]P_{ij}=P_{ji}[/itex]?
latentcorpse Messages 1,411 Reaction score 0 Apr 26, 2009 #3 do you mean just substitute in numbers and see what happens because that works - i was just wondering if i could do it without explicitly using numbers (i.e. all of it in index notation).
do you mean just substitute in numbers and see what happens because that works - i was just wondering if i could do it without explicitly using numbers (i.e. all of it in index notation).
dx Homework Helper Messages 2,143 Reaction score 52 Apr 26, 2009 #4 For i = j, clearly Aij = Aji, so you only need to check the cases in which i ≠ j. For example, setting i = 1 in εijkAkj = 0, you get ε123A32 + ε132A23 = A32 - A23 = 0 ⇒ A32 = A23. You just need to do the same with i = 2 and i = 3.
For i = j, clearly Aij = Aji, so you only need to check the cases in which i ≠ j. For example, setting i = 1 in εijkAkj = 0, you get ε123A32 + ε132A23 = A32 - A23 = 0 ⇒ A32 = A23. You just need to do the same with i = 2 and i = 3.