MHB How to show uniqueness in this statement for integers

AI Thread Summary
The statement claims there exists a unique integer n such that n^2 + 2 = 3. The proof shows that n can be either -1 or +1, indicating two valid integer solutions. This demonstrates that the solution is not unique, as both integers satisfy the equation. The discussion emphasizes that the uniqueness fails when considering all integers, including negatives. Therefore, the statement is disproven by the existence of multiple solutions.
cbarker1
Gold Member
MHB
Messages
345
Reaction score
23
Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.
 
Mathematics news on Phys.org
Cbarker1 said:
Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.

Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.
 
I like Serena said:
Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.

Yes, since I found two solutions to satisfy the equation. therefore, n is not unique.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...

Similar threads

Back
Top