How to show uniqueness in this statement for integers

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SUMMARY

The statement "There exists a unique integer n such that n² + 2 = 3" is not a theorem due to the existence of two integer solutions: n = -1 and n = +1. The proof shows that both values satisfy the equation, demonstrating that the solution is not unique. The discussion emphasizes the importance of considering the set of integers, which includes both positive and negative numbers, in determining uniqueness.

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cbarker1
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Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.
 
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Cbarker1 said:
Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.

Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.
 
I like Serena said:
Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.

Yes, since I found two solutions to satisfy the equation. therefore, n is not unique.
 

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