MHB How to show uniqueness in this statement for integers

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The statement claims there exists a unique integer n such that n^2 + 2 = 3. The proof shows that n can be either -1 or +1, indicating two valid integer solutions. This demonstrates that the solution is not unique, as both integers satisfy the equation. The discussion emphasizes that the uniqueness fails when considering all integers, including negatives. Therefore, the statement is disproven by the existence of multiple solutions.
cbarker1
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Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.
 
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Cbarker1 said:
Dear Everyone,

Directions: Decide whether the statement is a theorem. If it is a theorem, prove it. if not, give a counterexample.

There exists a unique integer n such that $$n^2+2=3$$.

Proof:
Let n be the integer.

$$n^2+2=3$$
$$n^2=1$$
$$n=\pm1$$

How show this is unique or not? Please explain why if not.

Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.
 
I like Serena said:
Hi Cbarker1,

You found 2 integer solutions that indeed satisfy the equation.
Doesn't that mean that the solution is not unique?
Our counter example is the fact that both n=-1 and n=+1 are solutions.
It would be different if we were only looking at natural numbers, excluding negative numbers, but 'just' integers can be negative.

Yes, since I found two solutions to satisfy the equation. therefore, n is not unique.
 
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