How to Solve a Non-Exact Differential Equation with an Integrating Factor?

Ptopenny
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the problem is (x+x^4)dy+y(y^3-x^3)dx=0
well I know that this is not a separable equation, homogenous equation or an exact equation...so i try to solve it by treating it as a non exact DE by finding out the integrating factor...but the both IF come out in term of x and y which involve 2 variables where by IF must only has one variable...
 
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Hi !
The pattern of the ODE makes think to a change of variables : X=x^3 and Y=y^3, which leads to a Riccati ODE.
 

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thank god...u really help me very much :D :D
 
Thread 'Direction Fields and Isoclines'

Thread 'Direction Fields and Isoclines'

I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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