How to Solve for x or y in a Horizontal Tangent Problem?

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To solve the equation 4x - 2xy = 0, it can be factored into 2x(2 - y) = 0, leading to two possible solutions: x = 0 or y = 2. Substituting y = 2 back into the original equation shows that x can be any value, as the equation simplifies to 0 = 0. The discussion also explores an alternative equation, 2y^3 + 6(x^2)y - 12x^2 + 6y = 1, but focuses primarily on the first equation. The conclusion reached is that the solutions for x and y are x = 0 and y = 2. Understanding the factoring process is key to solving horizontal tangent problems effectively.
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Homework Statement



4x - 2xy = 0
how do i solve for EITHER x or y?

Homework Equations





The Attempt at a Solution



i got y = 2 at first but when i plugged it into the original equation to find x it was impossible to get an answer (the x's canceled out)
 
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brambleberry said:
i got y = 2 at first but when i plugged it into the original equation to find x it was impossible to get an answer (the x's canceled out)

the x doesn't cancel out.

4x-2xy=0
2x(2-y)=0

so 2x=0 or 2-y=0.

Meaning x=0,y=2
 
rock.freak667 said:
the x doesn't cancel out.

4x-2xy=0
2x(2-y)=0

so 2x=0 or 2-y=0.

Meaning x=0,y=2

the original equation is 2y^3 + 6(x^2)y - 12x^2 + 6y = 1
 
4x-2xy=0
4x=2xy
4=2y
2=y
4x-2x(2)=0
4x=2x(2)
4x=4x
x=1
4(1)-2(1)(2)
4-4=0
yeah i think that's right but not 100% sure
 
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