How to Solve Related Rates Problems: Calculating Egg's Shadow Speed"

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Homework Help Overview

The discussion revolves around a related rates problem involving the speed of an egg's shadow on the ground as it falls from a height of 20 feet. Participants are analyzing the scenario where a neighbor shines a flashlight on the egg, creating a shadow that moves as the egg descends.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss their methods for solving the problem, including setting up relationships between the height of the egg and the distance of the shadow. There are inquiries about the correctness of the answers obtained and the units used in calculations.

Discussion Status

Some participants express differing views on the correctness of the answers, with one agreeing with the book's solution. Others share their approaches and seek clarification on the methods used, indicating a collaborative exploration of the problem.

Contextual Notes

There is a noted discrepancy in the use of units, with one participant pointing out the need to use feet per second instead of meters per second for gravitational acceleration. This highlights a potential source of confusion in the calculations.

BrownianMan
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One night, a toddler is dropping eggs from a windowof a building which is 20 feet above ground. A neighbor, hearing the commotion, looks through her window which is 15 feet from the toddler's window, on the same wall of the building, and at the same height. She shines a flashlight from her window on one of the falling eggs. How fast is the shadow of this egg moving on the ground when the egg is halfway to the ground?

The prof did this in class and got an answer of 42 m/sec. The answer in the back of the book says 76 ft/sec. I get the same answer as the prof, but I'm not sure if it's correct.

Is the book wrong??
 
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I'm agreeing with the book.
 
How did you solve it?
 
BrownianMan said:
How did you solve it?

I drew a diagram, wrote down relations between sides, differentiated etc. This is a HW question. Show your solution and I'll look at it.
 
This is what I did:

I let h(t) be the height of the egg t seconds after being dropped, and let s(t) be distance at t seconds between shadow of egg and the point the egg hits the ground.

So tan(theta) = 20/(15 + s) = h/s. Hence, 20s = 15h + sh, and 20s' = 15h' + sh' + s'h.

h(t) = -4.9t^2 + 20
h'(t) = -9.8t

at h = 10:

10 = -4.9t^2 + 20
t = 10/7

and substituting into 20s = 15h + sh, I get s = 15. Then,

20s' = -15(9.8)(10/7) + 10s' + (-9.8)(10/7)(15)
s' = -42 ft/sec
 
BrownianMan said:
This is what I did:

I let h(t) be the height of the egg t seconds after being dropped, and let s(t) be distance at t seconds between shadow of egg and the point the egg hits the ground.

So tan(theta) = 20/(15 + s) = h/s. Hence, 20s = 15h + sh, and 20s' = 15h' + sh' + s'h.

h(t) = -4.9t^2 + 20
h'(t) = -9.8t

at h = 10:

10 = -4.9t^2 + 20
t = 10/7

and substituting into 20s = 15h + sh, I get s = 15. Then,

20s' = -15(9.8)(10/7) + 10s' + (-9.8)(10/7)(15)
s' = -42 ft/sec

That's pretty much what I did. For one thing the units of the problem are feet. You are using 9.8m/s^2 for g. That's the metric unit. You want 32 ft/s^2 in english units.
 
Ah, silly mistake!

Thanks, it all works now.
 

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