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a*(e^(2x)-e^x)+b*x=c

in terms of a, b, and c.

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- #1

- 2

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a*(e^(2x)-e^x)+b*x=c

in terms of a, b, and c.

- #2

Simon Bridge

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Welcome to PF;

And you want to find x given m and k.

That help?

Solving for x given a,b,c you mean? That would be the intersection of a line with a quadratic in e^x... that is $$ e^{x}\left ( e^x - 1\right ) = mx+k$$ ...where ##m=-b/a## and ##k=c/a##.solve: a*(e^(2x)-e^x)+b*x=c ... in terms of a, b, and c.

And you want to find x given m and k.

That help?

Last edited:

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Welcome to PF;

Solving for x given a,b,c you mean? That would be the intersection of a line with a quadratic in e^x... that is $$ e^{x}\left ( e^x - 1\right ) = mx+k$$ ...where ##m=-b/a## and ##k=c/a##.

And you want to find x given m and k.

That help?

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