How to Solve This Logarithmic Problem?

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To solve the logarithmic problem, the key formulas to use are nlog_a b = log_a b^n and log_a b = log_a c, which imply b = c. The discussion centers on manipulating the equation log(x-3)/3 = 1/2(logxy) to resemble x squared + y squared = 11xy. By applying the first formula to 1/2log(xy) and then using the second formula, the equation simplifies to (x-y)/3 = (xy)^(1/2). Squaring both sides leads to the final solution, resolving the problem effectively.
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You'll need these formulas

nlog_a b= log_a b^n

log_a b= log_a c \Rightarrow b=c

log_a x + log_a y = log_a xy
 
phy_ said:
if i use these formulas

log(x-3)/3 = 1/2(logxy)

i am not sure what i would then do to have the answer resemble x squared + y squared = 11xy.

you mean you'd get log(x-y/3)= 1/2log(xy)?

Use first formula on 1/2log(xy) and then apply the second formula.
 
Yes.

\frac{x-y}{3} =(xy)^{\frac{1}{2}}

Square both sides now.
 
Thank-you very much. Question solved.
 
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