How to solve this network of resistors for equivalent resistance?

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SUMMARY

The discussion focuses on solving a network of resistors to determine the equivalent resistance. Participants identified that segments PA and PB, as well as QA and QB, are in parallel, leading to a calculated equivalent resistance of 4 ohms when combined with series resistance from segment AB. The importance of recognizing parallel configurations and the potential impact of schematic representations on circuit analysis is emphasized throughout the conversation.

PREREQUISITES
  • Understanding of parallel and series resistor configurations
  • Familiarity with basic circuit schematic conventions
  • Knowledge of Ohm's Law and resistance calculations
  • Ability to analyze circuit diagrams
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  • Learn about the Thevenin and Norton equivalent circuits
  • Explore advanced resistor network problems and solutions
  • Investigate the impact of resistor values on overall circuit performance
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Electrical engineering students, hobbyists working on circuit design, and professionals involved in electronics who need to analyze and solve resistor networks effectively.

Harsharma17
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Homework Statement
The question asks to find the equivalent resistance for this group of resistors in a network.
Relevant Equations
I used Ohm's law and parallel and series combination to solve it, but don't know where to start. I thought about using Kirchoff's laws, but still I can't find the answer.
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Did you spot any resistors that are in parallel?
 
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Straight segment AB looks like the letter I. Would anything change if you replaced it with more straight segments that look like the letter H and tied the two resistors on the left to the left side of the H and likewise for the right side?

Remember, the convention is that, in a schematic circuit, any point on a straight line segment is at the same potential as any other point as long as there are no circuit elements, e.g. resistors, batteries, etc., in between.
 
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kuruman said:
Straight segment AB looks like the letter I. Would anything change if you replaced it with more straight segments that look like the letter H and tied the two resistors on the left to the left side of the H and likewise for the right side?

Remember, the convention is that, in a schematic circuit, any point on a straight line segment is at the same potential as any other point as long as there are no circuit elements, e.g. resistors, batteries, etc., in between.
Thanks for the reply!
Going through your suggestion, I think PA and PB are in parallel, and QA and QB are also in parallel. Solving them would lead to 2 ohm on each side of AB in series. And the equivalent resistance would be 4 ohm.
I got the answer! Thanks for the help.
 
gneill said:
Did you spot any resistors that are in parallel?
Yes, now I able to separate them in parallel circuits.
Thanks for the reply!
 

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