How to subtract signals using lock-in-ampl

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To subtract photocurrents from two photodiodes using a lock-in amplifier, the SR830 model can be utilized effectively. First, measure the currents from both photodiodes with the lock-in amplifier by connecting the reference frequency to the reference input and the signals to the measurement input. After obtaining the current measurements, the outputs can be fed into a storage oscilloscope for subtraction to analyze the difference in photocurrents. Understanding the settings for sensitivity, reserve, and time constant on the lock-in amplifier is crucial for accurate measurements. Consulting the lock-in amplifier's manual is recommended for detailed operational guidance.
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i want to subtract photocurrents from two photodiodes. please tell me how to do this. also please tell me how to measure current and voltage with a lock in amplifier.

Thank you very much
 
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There are many ways to subtract two signals. Are you planning to design your own circuit (using an op-amp), or two use an instrument (such as a summing amplifier)?

Can you be a bit more specific about the lock-in? Which model is it?
Some lock-in amplifiers have a current input meaning measuring a current signal is easy.

Measuring with a lock-in is also easy (but understanding what you are doing is a bit more tricky): connect the reference frequency to the ref input and the signal to the measurement input; set the sensitivity, reserve and time constant and the lock-in will show you the voltage/current.
For more specific instructions I would suggest reading the manual.
 
Thanks alot. well i am planning to do Homodyne detection. in this method, the photocurrets from two photodiodes need to be subtracted. there might be different ways to do this, the one that i want to do is to first measure both the currents using lock in. then feeding the ouput from lock into storage oscilloscope, i want to subtract them and see the photocurrents difference. the lock in model is SR830.

Thanks alot
 
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