Fortran How to swap number in the fortran memory?

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To swap numbers in Fortran memory, one effective method is to use a temporary variable. For example, to swap the values of x(1) and x(2), assign x(1) to a temporary variable, then set x(1) to x(2), and finally assign the temporary variable to x(2). For sorting an array of numbers, a common approach is to implement a bubble sort algorithm. This involves iterating through the list, comparing adjacent elements, and swapping them if they are in the wrong order. A flag can be used to optimize the process by stopping the loop if no swaps occur during a complete pass through the array. The discussion concludes with a successful resolution to the initial query.
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how to swap number in the fortran memory??

hello..
im new to fortran so how i swap number in do loop
first the tracing is like this:

x(1)=3
x(2)=8

then, how to i can swap the number in x(1) and x(2)

can anyone help me
please...
 
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Why would you not use;

a=x(1)
x(1)=x(2)
x(2)=a

?
 


ok I am completely blank..
if i have to arrange these number(10,4,1)into ascending order..
what should i do..
 
Last edited:


Run through each number (to n-1) in the list (of n numbers) and swap over any where x(a) > x(a+1). Repeat. Set up a flag so you can stop if none are swapped during a repeat.
 


cmb said:
Run through each number (to n-1) in the list (of n numbers) and swap over any where x(a) > x(a+1). Repeat. Set up a flag so you can stop if none are swapped during a repeat.

thanks man!its solved..
credit to cmb...
 

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