How to work with non-constant forces?

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Homework Help Overview

The problem involves a 1 kg block being pushed by a non-constant force defined as x^2, where x is the displacement in meters. The objective is to determine the speed of the block at a displacement of 10 meters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the relationship between force, mass, and acceleration, with one attempting to integrate to find the velocity function. Others suggest applying the Work-Energy theorem and integrating the force to find the total work done. Questions arise regarding the validity of the approaches and the calculations involved.

Discussion Status

There are multiple interpretations of how to approach the problem, with some participants suggesting the use of integration to find work done and others exploring the Work-Energy theorem. Guidance has been offered regarding the need to integrate due to the non-constant nature of the force.

Contextual Notes

Participants note the initial condition of the block being at rest and the implications of using non-constant forces in their calculations. There is a recognition of potential confusion regarding integration and the application of the Work-Energy theorem.

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Homework Statement


A 1 kg. block at rest is pushed with a force of x^2, where x is the displacement (in meters). What is the speed of the object at 10 meters?


Homework Equations


F = ma


The Attempt at a Solution


I did x^2 = ma and found the acceleration by dividing the mass which is just 1. So a = x^2. I integrated to find the velocity function so I got [(x^3)/3] + C. It's initially at rest so at x = 0, the velocity is 0 which means C = 0 so I can get rid of that. If I plug in 10 meters into the velocity equation: (10^3)/3 I get 333.3 m/s. Solution says this is wrong but I have never worked with integration before so I'm not sure how to do this.
 
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I would consider using the Work energy theorem.
 
So the total work done is F*d. So that's 10x^2. Initial velocity is 0 at rest so change in KE = Work done: (1/2)mv^2 = 10x^2. Solve for v and it's sqrt(20)*x. At x = 10, I get v = 10sqrt(20). Is this right?
 
PhizKid said:
So the total work done is F*d.
The force is not constant. You'll have to integrate: W = ∫F(x)dx
 
So the total work done is (x^3)/3 ? So can I do:

(x^3)/3 = (1/2)mv^2
666.66 = v^2
v = 25.8 m/s ?
 
PhizKid said:
So the total work done is (x^3)/3 ? So can I do:

(x^3)/3 = (1/2)mv^2
666.66 = v^2
v = 25.8 m/s ?
Looks good to me.
 

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