HW: What is energy used? What is wattage?

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The discussion revolves around calculating the energy used by a camera flash and its wattage based on given capacitor specifications. The energy formula for a capacitor is clarified as E = 1/2 * C * V^2, leading to a correct energy calculation of 33J. For wattage, the power is derived from the formula P = E/t, resulting in a calculation of 8500W when using the correct energy value and flash duration. Participants emphasize the importance of using the correct formulas for energy and power calculations in electrical systems. The thread concludes with a focus on understanding the energy stored in capacitors and its implications for flash duration and intensity.
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Cutnell Physics 7th Ed pg 600 # 39

Homework Statement



A camera flash has a capacitor.
Capacitor has a rating of: 850uF
The potential difference between the places is: 280V

a) Determine Energy used to produce flash.
b)If flash lasts 3.9E-9 S, what is the power or wattage of the flash?

Homework Equations



V=C/F
W=VA
A=C/S

The Attempt at a Solution



a) (280V)(850uF)= 0.238C

b) (0.238 C)/(3.9E-3 S)= 61.03A
W=?

The back of the book has a) =33J b) 8500W
Where did I go wrong?

Thanks in advance.
 
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Energy = 1/2*C*V^2
Power = E/t
 
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