- #1

JumpinJohny

- 15

- 0

## Homework Statement

A flash attatchment for a professional camera stores energy in a capactior. When a picture is taken, all of the charge is converted to energy, and the capacitor is fully discharged.

A.Assume the battery charging the capacitor is a 300V battery. When the light flashes, it produces 5000W of light for a time of .005s. Find the total energy produced by the flash.

B.Find the capacitance.

C.If the battery were replaced with a battery with a potential difference of 120V, how much light power could the flash attachment produce?

## Homework Equations

C= q/V

PE = qV

U=(1/2)CV^2

## The Attempt at a Solution

I really don't know. At first I thought I'd just solve for capacitance(which you can't anyway), until I looked at part B. I'm assuming you need to solve for the potential energy of the flash, but I'm not sure how to go about doing that.