Hydrostatics- rearranging formula

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SUMMARY

The discussion focuses on deriving the equation for the pressure difference \( P - B \) in hydrostatics, utilizing variables such as \( \rho_m \) (density of the fluid), \( \rho \) (density of the liquid), \( L \) (length), \( \theta \) (angle), \( a \) (area of the tube), \( A \) (area of the reservoir), and \( g \) (acceleration due to gravity). The derived formula is \( P - B = (\rho_m - \rho)g(L \sin \theta) + (L \sin \theta + \frac{\rho}{\rho_m} + \frac{L_a}{A}) \). The discussion emphasizes the need for a sketch or additional description to clarify the problem further.

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Homework Statement



Derive an equation for the pressure difference p – B in terms of ρM, ρ, L, θ, a, A
and the acceleration due to gravity g

Homework Equations



(LHS p')= B+(ρm)g(Lsinθ+h+Δ) = (RHS p') P+ρg(Lsinθ+H)

Δ=delta = La/A

a= area of tube, A= area of reservoir

h= ρH/ρm


The Attempt at a Solution



P-B= ρmg(Lsinθ+(ρH/ρm)+(La/A)) - ρg(Lsinθ+H)

= (ρm-ρ)g(Lsinθ)+ (Lsinθ+(ρ/ρm)+(La/A)

I was just wondering if this is the correct formula for P-B
 
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A sketch or more of a description of the problem would be helpful here.
 

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