Hypothetical Acceleration of a Rock in Outer Space: Will it Continue Forever?

  • Thread starter Thread starter jhirlo
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
In a hypothetical scenario where a rock is given an acceleration of 10 m/s² in outer space, it will not continue to accelerate indefinitely. Acceleration applies only while a force is exerted on the rock. Once the force is removed, the rock will maintain its speed, moving at a constant velocity according to Newton's first law of motion. If a constant force is applied, the rock's speed will increase until it approaches the speed of light, at which point relativistic effects come into play. As the rock's speed increases, its relativistic mass increases, making further acceleration increasingly difficult. Thus, while it can accelerate initially, it cannot reach or exceed the speed of light.
jhirlo
Messages
40
Reaction score
0
Hypothetically, when I give acceleration to rock in outer space (nogravity, no air), e.g. 10m/s^2 will it continue to increase the speed forever or it'll (after some time) continue moving without acceleration, at constant speed (like 1.Newtons says, if you let them on their own, they'll be moving in constant speed or standing …) ?

Tnx!
 
Physics news on Phys.org
What do you mean by "give acceleration to rock in outer space"?
An acceleration only applies for as long as you apply it. You can't "give acceleration to rock" so that it permanently has that acceleration unless you attach a motor to it (even then it will eventually run down!). You have to apply the acceleration for a specific time. You could then calculate the increase in speed for that time to find the rock's new speed. The rock will then continue to move at that new speed.
 
Originally posted by HallsofIvy
What do you mean by "give acceleration to rock in outer space"?
An acceleration only applies for as long as you apply it. You can't "give acceleration to rock" so that it permanently has that acceleration unless you attach a motor to it (even then it will eventually run down!). You have to apply the acceleration for a specific time. You could then calculate the increase in speed for that time to find the rock's new speed. The rock will then continue to move at that new speed.
I think he means if you apply a constant force on a rock, what will be the speed at which the rock maxes out at, knowing it can't make it to the speed of light.. I guess like it's "terminal" speed
 
The rock will think its constantly accelerating according to Netwon's formula. An outside observer will see it asymptotically approaching C.
 
Originally posted by jhirlo
Hypothetically, when I give acceleration to rock in outer space (nogravity, no air), e.g. 10m/s^2 will it continue to increase the speed forever or it'll (after some time) continue moving without acceleration, at constant speed (like 1.Newtons says, if you let them on their own, they'll be moving in constant speed or standing …) ?

Tnx!

No. It's only possible for the acceleration to be constant, as measured in your frame of reference, while the speed is less than the speed of light. The faster the particle goes the harder it is to accelerate it. This is due to the fact that the (relativistic) mass increases with speed and will approach infinity as the speed approaches the speed of light.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top