I don't fully understand this question about cubic spline interpolation

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The discussion centers on cubic spline interpolation, specifically the formulation of natural cubic splines. Each spline is defined by the equation gi(x) = ai(x-xi)³ + bi(x-xi)² + ci(x-xi) + di, where i ranges from 1 to N for N+1 data points. The key conclusion is that with N cubic splines, there are 4N unknown parameters, necessitating 4N equations to solve for these parameters. The condition that b1 and bN+1 are zero simplifies the equations needed for the spline coefficients.

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Firepanda
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If each spline is given in the form of

gi(x) = ai(x-xi)3 + bi(x-xi)2 + ci(x-xi) + di

where i = 1 to N for N+1 data points.

Then given that b1 and bN+1 are zero (because the second derivatives are zero at the endpoints, due to this being a natural cubic spline), then there are N-1 equations for b2...bN.

Since we then use the value of bi to work out the unknowns ai, ci and di then there are four equations per i. Then since bi and bN+1 are zero, we can work out ai, ci and di on the last splines (3 each).

So is the answer 4(N-1) +6?

I don't understand what it means by 'Show there are enough equations..', any ideas?

Thanks
 
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Hi Firepanda! :smile:

If you have N+1 datapoints, that means you have N cubic splines.
Each spline has 4 unknown parameters for a total of 4N parameters.
To solve all parameters you need as many equations as parameters.

So you need exactly 4N equations...
 

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