fluidistic
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Homework Statement
P_0 (t+dt)=P_0(t)(1-\gamma dt ) (1)
Therefore P_0 (t)+\frac{dP_0 (t)}{dt} \approx P_0 (t)-\gamma P_0(t)dt. (2)
Where the approximation is due to a Taylor expansion apparently.
Homework Equations
Taylor expansion of f around x_0 : f(x)\approx f(x_0)+\frac{df(x_0)}{dx}(x-x_0).
The Attempt at a Solution
Considering that (1) holds true, I do not understand the implication. In other words I don't understand why (2) is true.
I also do not understand the Taylor expansion used in equation (2). What is the point being expanded around?
Thanks for any help!