I don't understand a step in my notes, about Taylor expansion

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SUMMARY

The discussion centers on the application of Taylor expansion in the context of a mathematical problem involving the function P_0(t). The user is confused about the transition from equation (1) to equation (2), specifically how the Taylor expansion leads to the approximation of the derivative. The key takeaway is that equation (2) is derived by expanding the function P_0(t) around the point t, which allows for the calculation of the first derivative using the Taylor expansion formula. The clarification provided by other users confirms the correct interpretation of the Taylor expansion in this context.

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Homework Statement


P_0 (t+dt)=P_0(t)(1-\gamma dt ) (1)
Therefore P_0 (t)+\frac{dP_0 (t)}{dt} \approx P_0 (t)-\gamma P_0(t)dt. (2)
Where the approximation is due to a Taylor expansion apparently.

Homework Equations


Taylor expansion of f around x_0 : f(x)\approx f(x_0)+\frac{df(x_0)}{dx}(x-x_0).


The Attempt at a Solution


Considering that (1) holds true, I do not understand the implication. In other words I don't understand why (2) is true.
I also do not understand the Taylor expansion used in equation (2). What is the point being expanded around?
Thanks for any help!
 
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From (1), they obtain an expression for the first derivative, using the definition of first derivative from the Taylor expanson. They then plug that in on the left hand side of (2) to obtain the right hand side.

Also, the function is expanded around the point t.
 
Sourabh N said:
From (1), they obtain an expression for the first derivative, using the definition of first derivative from the Taylor expanson. They then plug that in on the left hand side of (2) to obtain the right hand side.

Also, the function is expanded around the point t.
Hi Sourab, thanks for helping me.
Edit: I got it! thanks a lot!
 
Last edited:

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