I have a problem with some capacitors connected

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Two identical capacitors with the same voltage are connected in series, but one is submerged in oil, which acts as a dielectric and increases its capacity. When connected, the charge distribution between the capacitors changes due to the difference in capacity, affecting the voltage across them. If the capacitors are disconnected from the supply, the voltage will adjust, and if connected, a balancing current will flow. The presence of resistance in the connecting wires also plays a role in the energy variation during this process. Understanding these dynamics is crucial to resolving the energy discrepancies involved.
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I've found a problem about 2 identic capacitors which have the same voltage. One of them is sinked in oil and after that the 2 capacitors are connected in series. The problem ask for the for the energy variation. I've done the problem but I don't understand something:

When the capacitors are conected they must change charge between them because of the voltage difference. They alredy had the same charges and I know that two capacitors connected in series will have the same charge. So how is possible to change charge between them?
 
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What effect might the oil have on the capacitor?
 
skeptic2 said:
What effect might the oil have on the capacitor?

It fills the space between the capacitor's plates and change it's capacity, so as a result it's voltage will be changed.
 
Why will the oil change the capacitor's capacity and will it increase or decrease it?
 
skeptic2 said:
Why will the oil change the capacitor's capacity and will it increase or decrease it?

The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.
 
anachin6000 said:
The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.
If there is no external path leading from one end of a capacitor to its other end, then initial charge on its plates remains unchanged.
 
NascentOxygen said:
If there is no external path leading from one end of a capacitor to its other end, then initial charge on its plates remains unchanged.

When I said about charge Iwas referring to the topic question not to that capacitor.
 
anachin6000 said:
The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.

It is totally relevant to your original question.
Adding oil to one of the capacitors is changing its Capacity. When you do this and the capacitors are connected in parallel, the charges will no longer be equal (Q=CV) so the voltage will change (if disconnected from the supply) or some balancing current will flow if they are connected to a supply.

There is an extra factor that you need to consider and that is the energy expended in either case. There has to be a finite resistance in connecting wires or in the supply and you get a discrepancy in the before and after energy situation. This will be resolved if you allow the energy to be dissipated in the resistances.
 
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