I have a question and an answer for couette flow question

  • Thread starter Thread starter Goldberg
  • Start date Start date
  • Tags Tags
    Flow
Click For Summary

Discussion Overview

The discussion revolves around the analysis of Couette flow between two parallel plates, specifically focusing on the mathematical formulation and solution of the flow equations. Participants are exploring the integration process and the conditions necessary to derive the velocity profile in a laminar flow scenario.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant questions the necessity of adding constants after integrating the flow equations, suggesting there might be an easier method to arrive at the solution.
  • Another participant expresses a desire for a step-by-step solution to understand the basic concepts governing the equations, indicating difficulty in reaching a specific part of the solution.
  • A participant points out a potential equivalence in the measurement of the variable y in different examples, suggesting that the two approaches may yield the same results despite differing reference points.
  • Several participants report challenges in applying boundary conditions correctly, specifically using y=0 and y=h/2, and seek clarification on their approach to finding the correct solution.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best method to solve the problem, with multiple competing views on the integration process and boundary conditions remaining unresolved.

Contextual Notes

Participants express uncertainty regarding the application of boundary conditions and the integration process, indicating that assumptions about the flow characteristics and reference points may not be fully aligned.

Goldberg
Messages
10
Reaction score
0

Homework Statement


Fluid flows between 2 parallel plates, flow is fully developed and laminar, the distance between the plates is h
In the notes there is a general form of solution after integrating it 2 times. where a is h. but i saw in the book that we have to get +h/2 and -h/2 then add those equations find c1 and c2. but is there any easier way.
P.S. i wasn't able to find the final answer by using any of those things

Homework Equations


http://imgur.com/LwOFqy8

The Attempt at a Solution


http://imgur.com/0j2Ypr4
 
Physics news on Phys.org
a step by step solution would be awesome, since this is the beginning and i want to understand the basic concept ruling these equations. i have watched videos online everywhere but can't get to the last (1-(2h/y)^2) part
 
In one of your examples, y is measured up from the base, and the total channel height is a. In the other example, y is measured upward from the channel centerline, and the total channel height is h. The two examples are equivalent.

Chet
 
  • Like
Likes   Reactions: Goldberg
I tried solving it using y=o, when u=0
and y=h/2 when u=0.
still I am not able to find the same answer..
can someone tell me what's wrong
attempt jpeg:
http://postimg.org/image/u2srvitj7/
 
Last edited by a moderator:
Goldberg said:
I tried solving it using y=o, when u=0
and y=h/2 when u=0.
still I am not able to find the same answer..
can someone tell me what's wrong
attempt jpeg:
http://postimg.org/image/u2srvitj7/
For that case, you should be using u' = 0 at y = 0 and u = 0 at y = h/2.
 
Last edited by a moderator:

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
1
Views
10K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 13 ·
Replies
13
Views
11K