I have question,The electron and hole concentration in a intrinsic

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The discussion centers on the changes in electron and hole concentrations in intrinsic semiconductors when doped with p-type materials. Participants debate the correct equation that describes the relationship between these concentrations, with options including n+p = n1+p1 and np = n1p1. One participant suggests that the product of electron and hole concentrations remains constant, emphasizing that adding acceptor atoms increases hole concentration, which in turn affects electron concentration due to recombination. The consensus leans towards option (d), indicating that the product of the concentrations is a key principle in understanding semiconductor behavior. The conversation highlights foundational concepts in semiconductor physics for beginners.
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I have question,
The electron and hole concentration in a intrinsic semiconductor are n1 and p1 respectively.When doped with a p-type material these change to n and p repectively,then
a)n+p = n1+p1
b)n+n1= p+p1
c)np1 = n1p
d)np = n1p1

could anyone explain what would be the solution.
I am new to electronics and learning the concepts. I think the answer should be opton (b) as only electrons and holes can added before and after seperately.
 
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I think the Answer to your question should be (d).

When you start with the subject there is an explanation that product of the concentration of holes and electrons is always equal to a constant. Thus on addition of acceptor atoms there will be additonal holes which would alter the concentration of electrons also due to recombination but the fact that product of concentration is always a constant and is given by :- (For intrinsic semiconductor, n=p=[n(i)]^2 ) this constant always remains there !
 


Thanks for the update
 
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