I hope this helps, let me know if you need any further assistance!

waealu
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Homework Statement


(Sorry, but I haven't mastered using the sigma notation in these forums yet).

Find the sum of the following infinite series: (n=0)^(inf) SIGMA ((pi)cos(n))/(5^n).


Homework Equations


I tried using the formula S=(a1)/(1-r).

I know that a=pi, but I can't find "r." The equation doesn't have a consistent rate. Should I be using a different method?

Thanks.
 
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Hi waealu!

The sum you have wrote down is not a geometric series, so the formula you mentioned is not applicable (yet).

The problem is the cos(n), that spoils the fun. But there is a way to change the cos(n) into exponents by using the formula

\cos(n)=\frac{(e^i)^n+(e^{-i})^n}{2}

With this equation, you can express your series as a (sum of) geometric series.

Note, to display the sum with LaTeX, type

[ tex ] \sum_{n=0}^{+\infty} \frac{\pi \cos(n)}{5^n} [ /tex ]

without the spaces in the [ tex ] tags.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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