I need SERIOUS HELP integration by parts

In summary, the student is trying to integrate by parts but is having trouble understanding why it has to be repeated three times.
  • #1
BuBbLeS01
602
0
I need SERIOUS HELP...integration by parts!

Homework Statement


Integrate: x^3*e^x



Homework Equations





The Attempt at a Solution


I have the answer in my book but I am not understanding why you have to repeat the integration 3 times...

1.) dv = e^x dx
v = e^x
u = x^3
du = 3x^2

S=integral sign lol
S u*dv = uv - S v*du
S x^3*e^3 = x^3*e^x - S 3x^2*e^x dx

And now I have to do this 2 more times but I don't understand why and how I am supposed to know to do that?
 
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  • #2
[tex]I=\int x^3 e^xdx[/tex]

[tex]u=x^3[/tex]
[tex]du=3x^2dx[/tex]

[tex]dV=e^xdx[/tex]
[tex]V=e^x[/tex]

[tex]I=x^3e^x-3\int x^2e^xdx[/tex]

[tex]u=x^2[/tex]
[tex]du=2xdx[/tex]

[tex]dV=e^xdx[/tex]
[tex]V=e^x[/tex]

[tex]I=x^3e^x-3\left(x^2-2\int xe^xdx\right)[/tex]

Now do it again.
 
  • #3
But why? How do I know that I need to do this 2, 3, 4 times or whatever it may be?
 
  • #4
Well to me, just keep going till you've reduced it to where it is no longer a product, since Integration by Parts is the reverse of the product rule.

[tex]\int xe^xdx[/tex] = product

[tex]\int xdx[/tex] = not a product
 
  • #5
BuBbLeS01 said:
But why? How do I know that I need to do this 2, 3, 4 times or whatever it may be?

if it has an x^n * sin, cos, e^x, or any of those terms that repeat when integrated you will need to do integration by parts n times

for this problem you'll have:

x^3
3x^2
6x
1

you'll just keep repeating until the x^n term becomes 1.
 
  • #6
bob1182006 said:
if it has an x^n * sin, cos, e^x, or any of those terms that repeat when integrated you will need to do integration by parts n times

for this problem you'll have:

x^3
3x^2
6x
1

you'll just keep repeating until the x^n term becomes 1.
Yep, and those are called recurrent formulas, or recurrent integration.
 
  • #7
… the lesser evil …

BuBbLeS01 said:
But why? How do I know that I need to do this 2, 3, 4 times or whatever it may be?

Hi BuBbLeS01! :smile:

e^x is nice. We like e^x. It behaves itself.

x^3 is bad. We want to get rid of it.

So we wave our magic wand and make it smaller.

Then again. Then again, as many times as are necessary to make it disappear.

(They teach an incantation as well, at Hogwarts - but it's not strictly necessary.)

It's a tiresome job … but somebody has to do it …

It's just a good-versus-evil thing! :smile:
 

What is integration by parts?

Integration by parts is a method used in calculus to find the integral of a product of two functions. It is used when the integral cannot be computed using other methods, such as substitution.

When is integration by parts used?

Integration by parts is typically used when the integral involves a product of two functions, one of which can be differentiated and the other can be integrated. It is also used when the integral cannot be computed using other methods, such as substitution.

How does integration by parts work?

The integration by parts formula can be written as ∫udv = uv - ∫vdu, where u and v are the two functions involved in the integral. The goal is to choose u and dv in a way that simplifies the integral on the right side of the equation. This involves choosing u to be the function that becomes simpler after differentiation and dv to be the function that becomes simpler after integration.

What are the steps for integration by parts?

The steps for integration by parts are:
1. Identify u and dv in the integral.
2. Use the integration by parts formula to rewrite the integral.
3. Simplify the integral on the right side.
4. Integrate the remaining integral.
5. Solve for the original integral.
Note: Sometimes multiple iterations of integration by parts may be necessary to fully solve the integral.

Can integration by parts be used for definite integrals?

Yes, integration by parts can be used for definite integrals. The integration by parts formula can be applied to the limits of the integral, just like any other method of integration. However, care must be taken to choose u and dv in a way that simplifies the integral and matches the given limits.

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