I need serious help with this problem distance and area

  • #1
a. use 6 rectangles under the given graph of f from x=0 to x=12
(i)= L6 (sample points are left endpoints)
ii= r6 ('' '' '' '' right end point)
iii = m6 ('' '' '' '' are ,midpoints)

here is what i did, i sketched it already, y=f(x)

L6= 2 * 8.8 + 2 * 8 +.... 2 * 1 = 69.6
r6 = 2 * 9 + 2 * 8.8 +..... 2 * 4 = 85.6
m6= 1 (9) + 3(8.8) + 5 (8) .... 11 *4 = 222.4

is this right, i think i did it wrong because of it talks about sample points
 

Answers and Replies

  • #2
this is confusing, the only thing that confuses me is the sample points, what does that mean,
 
  • #3
does anyone understand what i'm saying
 
  • #4
Astronuc
Staff Emeritus
Science Advisor
20,163
3,738
It sounds like one is using rectangles to approximate the area under a curve, as opposed to trapezoids. However, as the width of the rectangles approaches zero, i.e. gets very small, then the sum of the areas of the rectangles approaches the exact area of under the curve.

The sample point is point x, for which the height, h = f(x)

The left sample points would be (0,f(0)), (2,f(2)), . . . (10,f(10)).

The right sample points would be (2,f(2)), (4,f(4)), . . . (12,f(12)), with the right side of the rectangle touching the curve f(x).

The mid sample points would be taken at 1, 3, 5, . . . 11 and with corresponding heights f(1), f(3), . . . f(11).

In all cases, if the 6 rectangles between 0 and 12 have uniform width, then all have width 2, and the area of each rectange = 2*f(x) where x is the sample point.
 
  • #5
so i did it right,
except M6 equals 85.6
2*f(1) + 2*f(3) ..... 2 f(11)=85.6
 
  • #6
HallsofIvy
Science Advisor
Homework Helper
41,847
967
a. use 6 rectangles under the given graph of f from x=0 to x=12
(i)= L6 (sample points are left endpoints)
ii= r6 ('' '' '' '' right end point)
iii = m6 ('' '' '' '' are ,midpoints)

here is what i did, i sketched it already, y=f(x)

L6= 2 * 8.8 + 2 * 8 +.... 2 * 1 = 69.6
r6 = 2 * 9 + 2 * 8.8 +..... 2 * 4 = 85.6
m6= 1 (9) + 3(8.8) + 5 (8) .... 11 *4 = 222.4

is this right, i think i did it wrong because of it talks about sample points
Well, where did you get those numbers, "8.8", "8", etc.? Presumably evaluated f(x) (actually got the values from the graph) for some values of x. How did you choose those values of x?
The problem said, first, "sample points are left endpoints" so you are expected to use the left end of each interval as the "x" value in f(x).
Then "sample points are right endpoints" so you should use the right end of each interval as "x" in f(x) for that interval.
Finally "sample points are midpoints" so you should use the midpoint of each interval as "x" in f(x) for that interval.
 

Related Threads on I need serious help with this problem distance and area

  • Last Post
Replies
5
Views
2K
Replies
2
Views
1K
Replies
6
Views
2K
  • Last Post
Replies
5
Views
1K
Replies
1
Views
999
Replies
15
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
4
Views
1K
Top