I need to find the velocity vector two results help please

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SUMMARY

The discussion centers on finding the velocity vector at time t=2s for the position vector r(t) = (50*sin((1/2)*t)*cos((1/4)t), -50*sin((1/2)*t)*sin((1/4)t)). The user calculated v(2) as (6.8, -15.7), which was confirmed as correct, provided angles are in radians. Another participant suggested an equivalent representation of the velocity vector as 25m/s*[0.272449, -0.62826], indicating that both answers are valid through factorization. The key takeaway is that different forms of the same vector can be mathematically equivalent.

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mimi.janson
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Homework Statement



find the velocity vector for the time t=2s

i have given r(t)=
(50*sin((1/2)*t)*cos ((1/4)t),
-50*sin((1/2)*t)*sin((1/4)t))

Homework Equations



i also know that r(t)=
(50*sin(k*t)*cos (1/2k*t),
-50*sin(k*t)*sin(1/2k*t))
where k = 0,5s-1

The Attempt at a Solution


so i tried solving it and my attempt is shown in the attachment where i got the result
v(2)=6,8;-15,7

but someone said it has to be solved with the following results
25m/s*[0,272449, -0,62826] so I am quite confused now..

so i don't know what to do and HOPE VERY MUCH someone will check my result v(2)=6,8;-15,7 and tell me if its right or not and if so what i can do to get the right result
 

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mimi.janson said:
so i tried solving it and my attempt is shown in the attachment where i got the result
v(2)=6,8;-15,7

but someone said it has to be solved with the following results
25m/s*[0,272449, -0,62826] so I am quite confused now..

so i don't know what to do and HOPE VERY MUCH someone will check my result v(2)=6,8;-15,7 and tell me if its right or not and if so what i can do to get the right result

Actually, your answer is correct if you refer angles with radians only. There seems to be no incorrect approach here.

What someone just did is to factor out 25 for each vector. Then, simplify the values. Yours and someone's answers are equivalent.

Nicely done!
 
NasuSama said:
Actually, your answer is correct if you refer angles with radians only. There seems to be no incorrect approach here.

What someone just did is to factor out 25 for each vector. Then, simplify the values. Yours and someone's answers are equivalent.

Nicely done!

Oh GREAT ! this answer is the one that has made me most happy ever <3

:)
 

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