I solving a proof relating sup(AB) and Binf(A)

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Homework Statement



Let A be a bounded nonempty subset of the set of all real numbers (R). B exists in R and B<0. Let BA= {Ba: a exists in A} Prove sup(BA)=Binf(A)

Homework Equations



We are able to use the ordered field axioms, Archemedian Property ect..

The Attempt at a Solution



I know that I need to show
that sup(BA)<=Binf(A) and sup(BA)>=BinfA
and If A is bounded then y<b where b is a bound for all y that exist in A
 
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cpl1992 said:

Homework Statement



Let A be a bounded nonempty subset of the set of all real numbers (R). B exists in R and B<0. Let BA= {Ba: a exists in A} Prove sup(BA)=Binf(A)

Homework Equations



We are able to use the ordered field axioms, Archemedian Property ect..


The Attempt at a Solution



I know that I need to show
that sup(BA)<=Binf(A) and sup(BA)>=BinfA
and If A is bounded then y<b where b is a bound for all y that exist in A

What is the definition of supremum and infimum?
 
Supremum is the lowest upper bound of the set and infimum is the highest lower bound of the set
 
cpl1992 said:
Supremum is the lowest upper bound of the set and infimum is the highest lower bound of the set
Ok, try thinking in terms of elements, that is, suppose i call β the supremum, how does that relate to elements in the set? And by supremum I'm referring to the supremum of set A.
Think about it, we have the ordered field axioms, a negative number, and the definition of sup and inf.
 
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I still seem to be confused as to how B would relate to the elements in the set. If B is sup(A) then this is saying it is the lowest upper bound of A. If this is the lowest upper bound then B could be either less than or greater than the set of BA itself correct?
 
cpl1992 said:
I still seem to be confused as to how B would relate to the elements in the set. If B is sup(A) then this is saying it is the lowest upper bound of A. If this is the lowest upper bound then B could be either less than or greater than the set of BA itself correct?

Try thinking of an example. Suppose I have the set A=(1,2) and B=-1
What is the supremum of B*A? What is B * infimum of A?

Does this help?

Also beta is not B, sorry i should have used a better letter. Beta is the supremum of the set.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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