Ideal gas law combined with vapor pressure

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Discussion Overview

The discussion revolves around the mathematical modeling of a steam espresso machine, focusing on the interactions between liquid water and gas in a closed container. Participants explore the implications of temperature and pressure changes on the system, particularly in relation to the ideal gas law and vapor pressure dynamics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant describes the system as a closed container with liquid and gas, noting that as temperature increases, vapor pressure rises while gas pressure follows the ideal gas law.
  • Another participant questions the conditions when the valve is opened, asking about heat supply and the exposure of gas to atmospheric pressure.
  • Clarifications are made regarding the presence of air in the headspace and how gas pressure affects the system when the valve opens.
  • Participants discuss the need to calculate pressures at different temperatures, particularly at 95°C, and how these relate to safe operating levels.
  • There is a focus on the relationship between vapor pressure and the pressure of atmospheric air, with some participants asserting that the increase in air pressure does not affect vapor pressure.
  • Questions arise about tracking pressure as a function of volume and the relationship between boiling point, vapor pressure, and atmospheric pressure in a closed system.

Areas of Agreement / Disagreement

Participants express differing views on the effects of atmospheric pressure on vapor pressure and the conditions under which water will boil in a closed system. The discussion remains unresolved regarding the exact calculations and implications of these pressures.

Contextual Notes

Participants highlight the need for specific temperature values and the importance of defining conditions such as whether the water can escape slowly from the container, which may affect fluid mechanics considerations.

Who May Find This Useful

This discussion may be useful for individuals interested in thermodynamics, fluid mechanics, and the practical applications of the ideal gas law in engineering contexts, particularly in the design and operation of pressurized systems.

zeebuck
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I am working on a DIY project and want to understand the system/mathematical model of a traditional steam espresso machine.

How I have started to think about the problem is a closed container with liquid and gas. At room temperature I know the vapor pressure of the water. As I increase the temperature the volume will stay the same. When the temperature increases the vapor pressure will also increase but at the same time the pressure of the gas should follow the ideal gas law. I am assuming for simplicity reasons that the liquid volume is not changing (the liquid to gas change is insignificant and the liquid won't compress).

Once the pressure/temperature reaches a set level the valve is opened. At this stage the temperature remains constant but the pressure decreases and volume increases.

Can I get help finding the equations during these different states to describe and calculate the system of the liquid and gas in the closed container (temperature and pressure based on the volume)?
 
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Is there air in the head space of your closed container?

I don't understand the situation when the valve is opened. Is heat supplied to the liquid to maintain its temperature? Is the gas exposed to the atmosphere, so that the pressure drops suddenly to atmospheric? How is the volume increasing; is this just that the gas is escaping from the container into the air?

Chet
 
Chet,

Thanks for the quick reply!

Yes there is air in the head on the container. For example the container is 500mL and only 300mL of water is poured in before being closed.

Once the valve is opened the pressure from the gas pushes the hot water through a tube at the bottom of the container. This way the gas isn't exposed to the atmosphere and as the water is pushed out the volume of the gas increases and the pressure decreases.
 
It still isn't clear to me exactly what you want to calculate after the valve is opened. And, in the first part, it would be better if you specified the temperature that the chamber is heated to. Then we could put some numbers on it.

Chet
 
I am sorry for not being clear.

Step 1-
When I put the water in and begin to increase the temperature, I need to calculate the pressure to ensure everything is operating at safe levels. My main confusion here is as the temperature increases the vapor pressure increase but following PV=nRT the gas pressure will also increase. IF the gas pressure increases does this effect the rate of the vapor pressure increasing?

Step 2-
Once the temperature is increased to a set/threshold level (this level is also dependent on the associated pressure) and the valve is opened, I would like to be able to track the pressure after the valve is opened.

Ideally the temperature before the valve is opened would be 90-95 degrees C however if the pressure at 95 C is too much I will have to decrease the threshold temperature to ensure the valve is opened at a lower temperature so the pressure is lower.
 
OK. You're going to help me do part 1. The pressure in the container is going to be determined by the pressure in the head space. The pressure in the head space is going to be the sum of the "partial pressure" of the water vapor and the partial pressure of the air. Initially, the temperature is going to be 20 C (293 K). The partial pressure of water vapor at this temperature is negligible, and the partial pressure of the air is going to be 1 atm (100 kPa). At 95C, the partial pressure of the water vapor is going to be equal to the equilibrium vapor pressure of water at that temperature. Look up the equilibrium vapor pressure of water at 95C. What is it? The partial pressure of the air in the head space is going to be determined by the ideal gas law. If the pressure of the air at 20C is 100kPa, what is the pressure of the air at 95C (from the ideal gas law)? What is the sum of the water vapor and air partial pressures at 95C?

I'll wait to hear back from you with these answers?

Chet
 
the pressure do to water vapor at 95 C is .83421 atm

the pressure of the atmospheric air at 95 C is 1.256 atm

this results in a total pressure of 2.09 atm

Does the increase in pressure of the atmospheric air have any effect on the vapor pressure of water? Also with the increase of pressure the boiling point of the water increases does this effect the vapor pressure?
 
zeebuck said:
the pressure do to water vapor at 95 C is .83421 atm

the pressure of the atmospheric air at 95 C is 1.256 atm

this results in a total pressure of 2.09 atm

Does the increase in pressure of the atmospheric air have any effect on the vapor pressure of water?
No.
Also with the increase of pressure the boiling point of the water increases does this effect the vapor pressure?
No.

What units do you want to work in: atm, psi, Pa, kPa?

Do you want to use gauge pressure or absolute pressure. Right now, 2.09 atm. is absolute pressure.

Chet
 
any units are fine to work in, converting across them is not too complex. Absolute pressure is also good. I am simply using these calculations to estimate/monitor the pressure across the temperature to make sure I don't exceed the system limits.
 
  • #10
zeebuck said:
Step 2-
Once the temperature is increased to a set/threshold level (this level is also dependent on the associated pressure) and the valve is opened, I would like to be able to track the pressure after the valve is opened.
What do you mean by wanting to track the pressure. Do you want it as a function of volume of water expelled, or as a function of time?

Chet
 
  • #11
Tracking pressure as a function of volume. Another question I have is how does the boiling point of the water change over the increase of temperature/pressure of the system? Because what I have read is the water will boil when the vapor pressure reaches the atmospheric pressure but in the closed system the atmospheric air pressure continues to increase with the temperature. Is there a temperature where the water will begin to boil?

Thanks for all the help so far!
 
  • #12
zeebuck said:
Tracking pressure as a function of volume. Another question I have is how does the boiling point of the water change over the increase of temperature/pressure of the system? Because what I have read is the water will boil when the vapor pressure reaches the atmospheric pressure but in the closed system the atmospheric air pressure continues to increase with the temperature. Is there a temperature where the water will begin to boil?

No.

If you are going to track pressure as a function of volume, then are you permitted to allow the water to escape very slowly from the bottom? If not, you may need to include the fluid mechanics in the channels beneath the chamber.

Chet
 

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