Ideal Gas Law Problem: Solving Pressure & Bottle Purge

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SUMMARY

The discussion revolves around calculating the pressure of argon gas in a 55.0 mL canister containing 26.0 g of argon at 295 K using the Ideal Gas Law (PV=nRT). The first part of the problem was solved successfully, but the second part, which involves determining how many 750.0 mL wine bottles can be purged with the argon at a pressure of 1.20 atm and a temperature of 296 K, remains unresolved. Participants emphasize the need to apply the Ideal Gas Law correctly to find the volume of decompressed argon and subsequently calculate the number of bottles that can be filled.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of molar mass calculations, specifically for argon
  • Basic principles of gas behavior under varying pressure and temperature
  • Familiarity with unit conversions, particularly volume from mL to L
NEXT STEPS
  • Calculate the pressure of argon in the canister using the Ideal Gas Law
  • Determine the volume of argon gas when released at 1.20 atm and 296 K
  • Learn how to convert between different volume units (mL to L) for gas calculations
  • Explore real-world applications of the Ideal Gas Law in gas storage and dispensing systems
USEFUL FOR

Students studying chemistry, particularly those focusing on gas laws, as well as professionals in fields involving gas storage and dispensing systems, such as winemaking or food preservation.

Bashyboy
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Homework Statement



A wine-dispensing system uses argon canisters to pressurize and preserve wine in a bottle. An argon canister for the system has a volume of 55.0 mL and contains 26.0 g of argon. Assuming ideal gas behavior, what is the pressure in the canister at 295 K? When the argon is released from the canister it expands to fill the wine bottle. How many 750.0 mL wine bottles can be purged with the argon in the canister at a pressure of 1.20 atm and a temperature of 296 K?

Homework Equations





The Attempt at a Solution



I was able to solve the first question, but unable to do the second. I tried to solve it by setting the ideal gas equation to n; which, I thought, would represent the number of wine bottles, but it didn't. How do I solve the second question?

Thank you.
 
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How many 0.75L bottles will the decompressed argon fill?
 
I honestly do not know. I am sorry.
 
OK, what is the volume of the decompressed argon?
 
Hi Bashyboy! :smile:

Let's start with the relevant equations.
Did you already have:
PV=nRT?
Molar mass of Argon?
 
I like Serena said:
Did you already have:
PV=nRT?
Molar mass of Argon?

I assumed he solved first part he applied these things. But perhaps I assumed too much...
 

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