Ideal Voltage in Series w/ resistance

AI Thread Summary
The discussion revolves around determining the power absorbed by a 10Ω resistor connected to an ideal voltage source in series with a resistance. Participants clarify that the resistors are connected one at a time, replacing the previous one, and that the resistances listed are likely equivalent resistances rather than individual values. There is confusion regarding the behavior of current as resistance increases, with one participant noting that current should decrease with higher resistance, contradicting the observed results. This discrepancy raises questions about the modeling of the device and the internal resistance of the voltage source. The conversation highlights the need for a clearer understanding of circuit behavior and the implications of the measurements taken.
shane317
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Homework Statement



A device can be modeled using an ideal voltage source in series with a resistance. That
device is shown in Figure P2.2. A set of resistors was connected to the terminals of the device, one at a time, and the voltage at the device terminals, vt, was measured in each case. The results are shown in Table P2.2. Then, a 10[Ω] resistor was connected to the terminals of the device. Find the power absorbed by this 10[Ω] resistor, when it is connected to the device terminals.

Please see image


Homework Equations



KVL, KCL, Ohm's Law





The Attempt at a Solution



I need help setting up the problem. The resistors are connected one at a time, but are they connected in series with respect to each other or parallel with respect to each other.

I assume the resistances given in the table are Req as opposed to the value of the individual resistors added to the circuit. I am also assuming the final 10 ohm resistor is connected after the three resistor set is removed.

Thank you, any help is greatly appreciated.

Shane
 

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I believe that each resistor replaces the precedent one.
 
CEL said:
I believe that each resistor replaces the precedent one.


OK, say the ideal voltage source and the internal resistance Rsource are in series to illustrate the device in question between terminals A and B. Each resistor in the table is connected to the terminals A and B one at a time and the resistances in the table are the resistances of the three resistors. So now to model the device I need to solve for the internal resistance(Rsource) and from there I can figure out the rest.

Thanks for the reply,

Shane
 
You're welcome!
 
There might be a problem with this question.

The current into the load resistor is increasing as the resistor value increases. (0.6A 1.6A 5.6A)

If the device in the box was a voltage source in series with a resistor, you would expect the current into the load to decrease with increasing resistance.

This increased resistance and reduced current are what causes the internal voltage drop to be less.
 

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