If A,B denumerable prove AUB denumerable

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SUMMARY

The discussion focuses on proving that the union of two denumerable sets, A and B, is also denumerable. It establishes that since A and B are denumerable, there exist bijections f: N → A and g: N → B. The proposed function h(n) is defined to combine these mappings, where h(n) = f(n/2) for even n and h(n) = g((n+1)/2) for odd n. This construction demonstrates that A ∪ B can be mapped to the natural numbers, confirming its denumerability.

PREREQUISITES
  • Understanding of denumerable sets and bijections
  • Familiarity with functions and mappings in set theory
  • Knowledge of injective functions and their properties
  • Basic concepts of natural numbers and their properties
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  • Study the properties of bijections and their applications in set theory
  • Learn about injective functions and their role in proving set denumerability
  • Explore the concept of unions of sets and their implications in mathematics
  • Investigate other proofs of denumerability for different types of sets
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This discussion is beneficial for students studying set theory, mathematicians interested in foundational concepts, and anyone looking to understand the properties of denumerable sets and their unions.

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Homework Statement


Prove that if A and B are denumerable sets, not necessarily disjoint, then AUB is denumerable.


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The Attempt at a Solution


So I started my saying that since A and B are denumerable then, f:N-->A and g:N-->B are bijections. The I defined h(n) in terms of f and g as such:
h(n) = f(n/2) if n is even
h(n) = g((n+1)/2) if n is odd
This is all I have so far. I am not sure where to go or what this tells me.
 
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Try mapping the sets to the naturals, the maps have to be injective. A hint is that n->2n is an injection and composition of injective functions is injective.
 

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