If an atom was scaled up to the size of a sports oval with a diameter of 150m ?

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The discussion centers on the scaling of an atom to the size of a sports oval with a diameter of 150 meters. It establishes that the nucleus of an atom, when scaled, would be approximately 1.5 mm in diameter, based on the ratio of 100,000:1 between the atomic diameter and nuclear diameter. The formula for nuclear radius is discussed as A^(1/3)*r, where A is the mass number and r is 1.2 x 10^(-15) m. The conversation highlights the complexity of atomic and nuclear dimensions, which vary by element.

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AHUGEMUSHROOM
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How big would the nucleus be?
A grain of sand (0.1cm diameter)
A marble (1cm diameter)

It's a grain of sand right(?); since the relationship between the diameter of an atom and its nucleus is 100,000 to 1. 150/0.001= 150,000
 
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Well, that depends on the element you're looking at. Different elements have different ratios of atomic radius to nuclear radius (as you increase Z, you get different Coulombic forces as you add electrons, not to mention you add electron shells). I don't know the mathematical formula(s) to find atomic radii, as I assume they're fairly complex, my best advice would be to look them up on some table. Nuclear radius goes something like A^(1/3)*r, where A is the mass number (number of protons and neutrons) and r = 1.2*10^(-15)m (the radius of a proton/neutron I believe). This is just derived from the volume and radius relation of a sphere, so this probably doesn't hold as well for smaller values of A (as the nucleus isn't quite so spherical I would think, except for A=1, hydrogen, with no neutrons, as its nucleus is just a proton), but for larger values it should work decently.
 
AHUGEMUSHROOM said:
How big would the nucleus be?
A grain of sand (0.1cm diameter)
A marble (1cm diameter)

It's a grain of sand right(?); since the relationship between the diameter of an atom and its nucleus is 100,000 to 1. 150/0.001= 150,000

(150 m) / (100,000) = (1.5 x 102 m)/(1.0 x 105) = 1.5 x 10-3 m = 1.5 mm
 

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