If distance and time can change then how can c be constant?

ChristianKing
Messages
2
Reaction score
0
If distance and time can change then how can c be constant? I guess what I'm asking is how can someone prove that c=c' without relying on c in a solution such as setting the Lorentz space contraction over the Lorentz time dilation?
 
Physics news on Phys.org


The Lorentz transformations cancel.
 


ChristianKing said:
If distance and time can change then how can c be constant? I guess what I'm asking is how can someone prove that c=c' without relying on c in a solution such as setting the Lorentz space contraction over the Lorentz time dilation?
If you're talking about the speed of light in a single direction (as opposed to measuring the two-way speed by sending a light beam away from a clock, having it bounce off a mirror and return to the clock, and using that time interval to divide the distance from the clock to the mirror and back), you can't derive it from length contraction and time dilation alone, you also have to take into account the relativity of simultaneity. I gave a numerical example of how it all works out in post #7 of this thread.
 


thank you
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Replies
14
Views
1K
Replies
36
Views
4K
Replies
60
Views
5K
Replies
58
Views
3K
Replies
46
Views
4K
Replies
27
Views
2K
Replies
25
Views
2K
Back
Top