If I had ((9-8.8))/8.8 how many sig figs would my answer have

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The calculation ((9-8.8))/8.8 results in an answer with one significant figure, as the subtraction yields 0, which has no significant figures. If the "9" is considered a measured quantity, it is treated as having one significant figure, indicating a range between 8.5 and 9.5. However, if "9" is treated as a counted quantity, it is exact and can have any number of significant figures. In a different scenario where "9" is expressed as 9.0, the result would be 0.023, which has two significant figures due to the precision of the measured quantities involved. Understanding significant figures is crucial in calculations, particularly in scientific contexts.
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If I had ((9-8.8))/8.8 how many sig figs would my answer have
 
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billabuwl50 said:
If I had ((9-8.8))/8.8 how many sig figs would my answer have
Only one sig fig. Since 9-8.8 = 0. and 0./8.8 = 0.

On a side note: sig figs are really funny. You use 'em in high school but you never really use 'em afterwards (OK, maybe in chemistry but that's it).
 
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Sig figs were my least favorite part of physics.
 
Is the "9" a measured quantity or counted? If measured, then the fact that you only give one figure means it has only one significant figure- it could be anywhere between 8.5 and 9.5. If counted, then it is exact and can have any number of significant figures.

In the first case, as swapnil said, it is (9- 9)/8.8= 0

In the second, (9.0- 8.8)/8.8= 0.2/8.8= 0.023 (or, better, 2.3 x 10-2. The result has 2 significant figures because the "measured quanities", the "8.8"s have 2 significant figures.
 
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