If the mass of the moon were tripled and it was moved to half as far f

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If the mass of the moon were tripled and its distance from Earth halved, the gravitational force between them would increase to 12 times the original force. A user seeks confirmation on this calculation. Additionally, a separate question about the acceleration of a 12 kg box on a ramp at a 30-degree angle with a coefficient of kinetic friction of 0.20 is discussed. The calculated frictional force is confirmed to be 20.36N, but clarification is needed on the correct method to find the box's acceleration. The discussion highlights the importance of accurately determining the components of weight acting on the ramp.
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>>>If the mass of the moon were tripled and it was moved to half as far from the centre of the Earth as it now rests, what would the new gravitational force between the Earth and the moon be?


Can someone confirm with me that the answer is 12 times the original?


>> A 12 kg box is sitting on a ramp which is angled at 30deg
to the horizontal. If the coefficient of kinetic friction is 0.20, what is the acceleration of the box down the ramp? (Assume static friction is not high enough to prevent it from moving.)

I got an answer of 20.36N, can someone double check that for me too?

fk = uk Fn = (0.2)(101.8N) = 20.36N

Fn = (12)(9.8)cos 30 = 101.8N
 
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Hi, oneshot. Welcome to PF.

Correct on the first question.

You still need to find the acceleration for the second question.
 
oh right, thanks
Fnet is mg cos 30 - fk right
and then use Fnet = ma and solve for a
 
oneshot said:
oh right, thanks
Fnet is mg cos 30 - fk right
and then use Fnet = ma and solve for a

Cos 30 is not correct for getting the component of the weight parallel to the ramp.
 
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