I'm sorry, I meant the x and y planes, not the z and y planes.

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SUMMARY

The discussion centers on solving a static equilibrium problem involving a 1125 N force supported by cable AD and struts AB and AC. The vectors for these components were calculated as <0,6,4> for AD, <-1,6,-2> for AB, and <4,6,-2> for AC. The user encountered difficulty in incorporating the 1125 N force, which acts solely in the yz plane, into the equilibrium equations. Clarification was provided regarding the proper identification of planes and the negative z component in the vectors.

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Homework Statement



A 1125 N force F is supported by cable AD and by struts AB and AC as shown. If the struts can transmit only axial tensile or compressive forces, determine the forces in the struts and the tension in the cable.

a = 6 m

b = 1 m

c = 4 m

d = 6 m

f = 2 m

[PLAIN]http://img714.imageshack.us/img714/773/cbb026135set3dconcurren.png


The Attempt at a Solution



Well I set everything up by first finding vectors AD, AB, and AC, which come out to be, respectively, <0,6,4>, <-1,6,-2>, <4,6,-2>. I then proceeded to solve for the Force vectors by components and got:

(vec)Fad = 0i(Fad) + .83205j(Fad) + .5547k(Fad)
(vec)Fab = -.156174i(Fab) + .93704j(Fab) - .31235k(Fab)
(vec)Fac = .53452i(Fac) + .80178j(Fac) + .26726k(Fac)

Then I set them up for a matrix

(Sum)Fx = 0i(Fad) - .156174i(Fab) + .53452i(Fac)
(Sum)Fy = .83205j(Fad) + .93704j(Fab) + .80178j(Fac)
(Sum)Fz = .5547k(Fad) - .31235k(Fab) + .26726k(Fac)

The problem that I am having is that the given force of 1125 N lies in both the z and y planes. How exactly do you implement that force into your equations to solve for the variables?
 
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F = 0*i + 0*j - 1125*k.

CB4: When you determined vectors AB and AC in post 1, I am not yet understanding why you listed the z component as negative.

By the way, when you talk about a plane, you must use two letters to describe the plane (xy, yz, or xz). Therefore, I do not know which planes you are referring to in your question, because you only used one letter. F lies in only one plane, the yz plane.
 

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