How to Correctly Solve L = 1800cc - 72cm?

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The discussion centers on solving for the length of a rectangular box that must hold 1,800 cubic centimeters, given a width of 12 centimeters and a height of 6 centimeters. Participants clarify that subtracting a length from a volume is incorrect and emphasize the need to use the formula for volume, V = l * w * h. The correct approach involves rearranging the formula to solve for length, leading to the equation l = V / (w * h). The final calculation confirms that the length can be determined by dividing the volume by the product of width and height. This method effectively resolves the initial confusion regarding the problem.
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I'm stuck can anybody help me? (Note: I'm looking for the length.)

1,800cc-72cm=L

What do I do next?
 
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Well, what you've posted does not make sense. You cannot subtract a length (cm) from a volume (cc). Perhaps you can show us the WHOLE problem?

- Warren
 
Well maybe I haven't got it written out right. Can I give you the problem and you work it out and show me how to do it?
 
Like I just said, yes, please post the entire problem.

- Warren
 
Here it is.

How long must a rectangular box be in oder to hold 1,800 cubic centimeters if its width is 12 centimeters and its height is 6 centimeters?
 
Originally posted by Superman89
Here it is.

How long must a rectangular box be in oder to hold 1,800 cubic centimeters if its width is 12 centimeters and its height is 6 centimeters?
Okay, you've already posted this once. Why did you start a new thread on it?

Here's how to solve it:

\begin{equation*}<br /> \begin{split}<br /> V &amp;= w \cdot l \cdot h\\\\<br /> l &amp;= \frac{V}{w \cdot h}\\\\<br /> l &amp;= \frac{1,800}{12 \cdot 6}<br /> \end{split}<br /> \end{equation*}<br />

Does this make sense?

- Warren
 
Let me see if I've got this straight.

When "w" and "h" are brought arcross the "=" sign, the oppisite must be done.

V=l*w*h

\frac {V}{w*h}=l

Right?
 
It's easier to think about it this way: performing the same operation to both sides of an equation does not change the equation's validity.

In other words, if you have an equation like a=b, adding one to both sides of it does not change its truth: a+1=b+1 is also true.

In the case of the equation V = l \cdot w \cdot h, you can divide both sides by w \cdot h and not change the equation's valitiy.

\begin{equation*}<br /> \begin{split}<br /> \frac{V}{w \cdot h} &amp;= \frac{l \cdot w \cdot h}{w \cdot h}\\\\<br /> \frac{V}{w \cdot h} &amp;= l<br /> \end{split}<br /> \end{equation*}

- Warren
 
I see what you mean. So my answer is going to be l &amp;= \frac{1,800}{12 \cdot 6}\end{split}\end{equation*}?
 
  • #10
Didn't I already say that?

- Warren
 
  • #11
Thanks! You've been a real good help Dude!
 
  • #12
Originally posted by Superman89
Thanks! You've been a real good help Dude!
Anytime. :smile:

- Warren
 
  • #13
Originally posted by Superman89
I'm stuck can anybody help me? (Note: I'm looking for the length.)

1,800cc-72cm=L

What do I do next?

Well fisrt thing I'd do is to get that X-Ray vision tested there Superman. ;)

Looks to me like when you copied the "answer" of L = 1800cc - 72 cm from whoever that you misread a divide symbol for a minus symbol.
 
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