Hi, I'm not sure if this is calculas based or algebra based so here's the question.

(
(A) 2i, -2i

For this question i don't know what is being asked so i guess the pairs could be x...
I know this:
ax^2+bx+c, a(x-h)^2+k and a(x-s)(x-t)
So the problem is how can i use the things that i know to answer the question. If you can please use analogies and don't give me the answer i just need to know what to do.

I doubt that hootenay... I'm thinking of x = -b -+ Square root of b^2-4ac over 2a equation and deriving it so that something will occur... im confused...

Like hoot implied(I think slightly incorrectly), it's always true that if r1 and r2 are the two roots to a quadratic then the characteristic quadratic equation is (x-r1)(x-r2)=0. Then you just expand that to get it into the standard form.

The same argument can be extended to higher degree polynomial equations.

My davey jones's locker i think ive got It!!
Correct me if i'm right
0=(x-(2x))(x-(-2x))
0=(x-2i)(x+2i)
0=(x^2+2ix-2ix-4i)
0=(x^2+4)
am i correct?
now if the pairs were 1+3i, 1-3i I would have sub the same way like
0=(x-(1+3i))(x-(1-3i))
0=(x-1+3i)(x+1-3i)
and solve from that correct?

You made a small mistake when going from the first line to the second line. Your second line should reads:
0 = (x - 1 - 3i) (x - 1 + 3i).
Now just expand all the terms out, simplify it, and it's all done.
Can you go from here? :)