- #1
seang
- 184
- 0
Hey, I'm finding equivalent impedances of circuits, and I always run into things like this:
1/(-j25) + 1/(600 +j900) = 1/Zeq
I don't know how to proceed from here. I know this is more of a math issue than anything else, but I appreciate your help
1/(-j25) + 1/(600 +j900) = 1/Zeq
I don't know how to proceed from here. I know this is more of a math issue than anything else, but I appreciate your help