The discussion focuses on differentiating the function y^2sin(x) using implicit differentiation. The correct application of the product rule and chain rule is essential for deriving the expression. The final derivative is confirmed as 2yy'sin(x) + y^2cos(x), demonstrating the necessity of proper differentiation techniques in calculus.
PREREQUISITESStudents studying calculus, particularly those learning about implicit differentiation and differentiation techniques involving products and trigonometric functions.
No. Your expression is a product, so you need to use the product rule first.JessicaJ283782 said:Homework Statement
Differentiate using implicit differentiation y^2sin(x)
Homework Equations
I know you need the chain rule and the product rule to solve this
The Attempt at a Solution
So, it would be:
2yy' + y^2cos(x)
Is that correct?
Mark44 said:No. Your expression is a product, so you need to use the product rule first.
d/dx(y2sin(x)) = ?
emlekarc said:Oops! It should have been 2yy'sin(x)+y^2cosx