The discussion revolves around the differentiation of the expression y^2sin(x) using implicit differentiation. Participants are exploring the application of the chain rule and product rule in this context.
Some participants have provided feedback on the differentiation attempts, with one confirming a revised expression. There appears to be a productive exchange of ideas, although no explicit consensus is reached on the final form of the derivative.
There is a note of confusion regarding the identities of the participants, as some seem to be unaware that they are different individuals discussing the same problem.
No. Your expression is a product, so you need to use the product rule first.JessicaJ283782 said:Homework Statement
Differentiate using implicit differentiation y^2sin(x)
Homework Equations
I know you need the chain rule and the product rule to solve this
The Attempt at a Solution
So, it would be:
2yy' + y^2cos(x)
Is that correct?
Mark44 said:No. Your expression is a product, so you need to use the product rule first.
d/dx(y2sin(x)) = ?
emlekarc said:Oops! It should have been 2yy'sin(x)+y^2cosx