Implicit Differentiation: Solving for y' in y^2sin(x)

[JessicaJ283782]

Homework Statement

Differentiate using implicit differentiation y^2sin(x)

Homework Equations

I know you need the chain rule and the product rule to solve this

The Attempt at a Solution

So, it would be:

2yy' + y^2cos(x)

Is that correct?

 

[Mark44]

Homework Statement

Differentiate using implicit differentiation y^2sin(x)

Homework Equations

I know you need the chain rule and the product rule to solve this

The Attempt at a Solution

So, it would be:

2yy' + y^2cos(x)

Is that correct?

No. Your expression is a product, so you need to use the product rule first.

d/dx(y²sin(x)) = ?

 

[emlekarc]

No. Your expression is a product, so you need to use the product rule first.

d/dx(y²sin(x)) = ?

Oops! It should have been 2yy'sin(x)+y^2cosx

 

[xiavatar]

That is correct.

 

[berkeman]

Oops! It should have been 2yy'sin(x)+y^2cosx

Are you guys in the same class or something?

 

[xiavatar]

Lolz. I barely noticed that they're two different people.