Improving Integration Skills: Solving a Tricky Integral Problem

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Homework Help Overview

The discussion revolves around solving a definite integral involving trigonometric functions, specifically integrating the expression ∫(cos^(1/2)(x))(1-cos^2(x))(sin(x)) dx from 0 to π/2. Participants are examining the original poster's approach and the resulting discrepancy between their answer and the expected solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve the integral using u-substitution, letting u=cos(x) and adjusting the limits accordingly. They express confusion over their final result of 7/6 compared to the expected answer of 8/21. Other participants question the application of limits and the correctness of the substitution process, suggesting that the original poster may have made errors in these areas.

Discussion Status

The discussion is ongoing, with participants providing guidance on checking the limits and the substitution process. There is a recognition that something went wrong in the original poster's calculations, but no consensus has been reached on the specific errors. Multiple interpretations of the integral setup are being explored.

Contextual Notes

Participants note the urgency of the original poster's situation, as they have an exam approaching. There is a focus on clarifying the limits of integration and ensuring that the substitution is applied correctly.

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Homework Statement



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Homework Equations



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The Attempt at a Solution



I set the integral as ∫(cos^1/2(x))(1-cos^2(x))(sinx) dx from 0 to π/2

Next I used u-substitution where I let u=cosx and du=-sinxdx

I solved out the integral and ended up getting 7/6 as my answer, however the correct answer is 8/21. Was my approach incorrect?
 

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You might be wrong in applying limits and simplifying. Check it. :)
 
Obviously, something went wrong, but we can't say unless you show the details of your work.
 
PhysicoRaj said:
You might be wrong in applying limits and simplifying. Check it. :)

Could you please tell me how I used the wrong limits, and what the actual limits are? (This question is really frustrating me and I have an exam in a few hours etc.).
 
Have you changed the limits according to your substitution?
The limits given are for x. Calculate them for u.
OR
have you replaced u by an x function?
 
SteamKing said:
Obviously, something went wrong, but we can't say unless you show the details of your work.

∫cosx^1/2(1-cos^2x)sinxdx

u=cosx
du=-sinxdx

-1∫u^1/2 - u

= -1((u^3/2)(2/3))(u^2/2)

= -1((cos^3/2(x))(2/3))cos^2(x)/2 -> Upper Limit = π/2 and Lower Limit =0

My answer comes out to 7/6, is the method that I used even correct? (Or should I have had used another method?)
 
student93 said:
∫cosx^1/2(1-cos^2x)sinxdx

u=cosx
du=-sinxdx

-1∫u^1/2 - u

= -1((u^3/2)(2/3))(u^2/2)

= -1((cos^3/2(x))(2/3))cos^2(x)/2 -> Upper Limit = π/2 and Lower Limit =0

My answer comes out to 7/6, is the method that I used even correct? (Or should I have had used another method?)

-1∫u^1/2 - u ...you have this wrong.
 
PhysicoRaj said:
-1∫u^1/2 - u ...you have this wrong.

How? I'm just really confused lol, shouldn't the be correct? Did I make a simple mistake?
 
√u(1-u2)
=√u-u2+0.5
=√u-u5/2
 
  • #10
PhysicoRaj said:
√u(1-u2)
=√u-u2+0.5
=√u-u5/2

Thanks, I'll try to see if I can get the correct answer now.
 

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