Impulse and Net Force Equations

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SUMMARY

The discussion focuses on deriving the net force equation for a falling elastic object, specifically a spring with a spring coefficient k. The net force equation is expressed as N - W - kx, where N is the normal force, W is the weight of the spring, and x is the compression distance. The main inquiry is whether there exists a point where N equals W + kx, and the implications of equilibrium in this context. The conversation emphasizes the necessity of using the work-energy theorem and integration due to the changing nature of the spring force over time.

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  • Familiarity with spring mechanics and Hooke's Law
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lehel
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I have a problem in trying to express a net force equation for a falling elastic object when collision ensues.

For instance, you drop a spring with a spring coefficient k. the spring compresses a distance x after a time t for a maximum time of tf and distance xf. the spring has a weight W. during the collision, the ground creates a normal force N which is the result of impulse.

thus, calling the direction upward the positive y-axis, the net force on y = N - W - kx. My question is, what does the net force along y equal? Actually, my real question is if there is a point where N = W + kx. But even if at a certain point there is no total accerlation, you would have an equilibrium equation would you not? Isn't that impossible because if the spring was in equilibrium for even a fraction of time dt, wouldn't it stay at rest?
 
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You are better attempting this question with the work-energy theorem. Because the force of spring changes over time, integration will be needed.

The maths is the easy part, visualizing the problem is were the work is.
 

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