Well, you're right that you're wrong. Given that the impulse [itex]I = m\Delta v[/itex], consider breaking the velocities into orthagonal components. Which component will the normal force change?miniradman said:
miniradman said:
, except that you've not yet multiplied by the mass I don't think so...tiny-tim said:hi miniradman! welcome to pf!
looks fine
(and do you need to specify the direction of the https://www.physicsforums.com/library.php?do=view_item&itemid=340" also?)
miniradman said:
…The impulse of a ball hitting the wall is the change in momentum that occurs when the ball collides with the wall. It is a vector quantity, meaning it has both magnitude and direction.
The impulse of a ball hitting the wall is calculated by multiplying the force of the impact by the time it takes for the impact to occur. This can be represented by the equation Impulse = Force x Time.
The mass of the ball does not directly affect the impulse, but it does affect the magnitude of the force of impact. A heavier ball will have a greater force of impact, resulting in a larger impulse.
Yes, the impulse of a ball hitting the wall can be negative if the direction of the force of impact is opposite to the initial direction of motion of the ball. This could occur if the ball is rebounding off the wall in the opposite direction.
The elasticity of the ball and wall can affect the impulse by influencing the force of impact and the amount of time it takes for the impact to occur. A more elastic ball and wall will result in a longer impact time and a smaller force of impact, leading to a smaller impulse.
