Impulse problem (intro mechanics)

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SUMMARY

The discussion focuses on calculating the impulse experienced by a rubber ball with a mass of 0.26 kg dropped from a height of 1.7 m, which bounces back with a speed of 3.6 m/s. The impulse is determined using the formula dp = Fdt = m(vf - vi), resulting in a magnitude of 2.4 kg·m/s. Additionally, the average force exerted by the floor is given as 17 N, leading to a contact time of 0.14 seconds with the floor. The calculations presented are confirmed to be accurate despite discrepancies reported by the electronic assignment system.

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  • Understanding of impulse and momentum concepts
  • Familiarity with Newton's laws of motion
  • Knowledge of kinematic equations for free fall
  • Basic proficiency in algebra for solving equations
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Homework Statement



A rubber ball (mass 0.26 kg) is dropped from a height of 1.7 m onto the floor. Just after bouncing from the floor, the ball has a speed of 3.6 m/s.
(a) What is the magnitude and direction of the impulse imparted by the floor to the ball? Magnitude ? kg · m/s

(b) If the average force of the floor on the ball is 17 N, how long is the ball in contact with the floor?


Homework Equations



dp=Fdt=m(vf-vi)

The Attempt at a Solution



a)the unknown is the initial speed of the dropping ball under free fall:

vi= sqrt (2 x 9.8 x 1.7) = 5.8

delta p= 0.26 (3.6--5.8)=2.4

b) dt=dp/Fave=0.14 s

Please let me know what is wrong here, my electronic assignment system is telling me the numbers are wrong. Thank you!
 
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