In a group, show that ord(x) = ord(yxy^-1)

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In summary, the conversation discusses a homework problem involving elements in a group and their orders. The conversation includes hints and attempts at solving the problem, including simplifying (yxy^-1)^n. The final response reminds the participants to consider the definition of "order" in their solution.
  • #1
Fairy111
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Homework Statement



If x and y are elements of a group G show that ord(x)=ord(yxy^-1)

Homework Equations





The Attempt at a Solution



Some hints to how to do this would be great.
 
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  • #2


What's (yxy^(-1))^n?
 
  • #3


y^n.x^n.y^(-n) ?
 
  • #4


Fairy111 said:
y^n.x^n.y^(-n) ?

You aren't going to get anywhere taking wild guesses. Try simplifying (yxy^(-1))^2=(yxy^(-1))(yxy^(-1)).
 
Last edited:
  • #5


that would be x^2
so (yxy^(-1))^n would be x^n
 
  • #6


Yes, that is correct. Now, what does that have to do with the definition of "order"?

Oops! Dick is correct. I forgot about the first and last y and y-1!

But, "what does that have to do with the definition of 'order'" still stands.
 
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  • #7


Fairy111 said:
that would be x^2
so (yxy^(-1))^n would be x^n

No. (yxy^(-1))^n would be yx^ny^(-1), NOT x^n. Be careful!
 

Related to In a group, show that ord(x) = ord(yxy^-1)

What does "ord(x)" represent in this statement?

"ord(x)" represents the order of the element x in the group, which is the smallest positive integer n such that x^n = e, where e is the identity element of the group.

Can you explain the concept of "showing" that ord(x) = ord(yxy^-1) in a group?

To "show" that ord(x) = ord(yxy^-1) in a group means to prove that the order of x and the order of yxy^-1 are equal. This involves demonstrating that both elements have the same smallest positive integer n that satisfies their respective equations, x^n = e and (yxy^-1)^n = e.

Why is it important to prove that ord(x) = ord(yxy^-1) in a group?

Proving that ord(x) = ord(yxy^-1) in a group is important because it helps us understand the structure and properties of the group. It also allows us to make conclusions about the relationship between the elements x and y and their powers, which can be useful in solving other mathematical problems.

What are some common methods for showing that ord(x) = ord(yxy^-1) in a group?

One common method is to use the fact that for any element x in a group, ord(x) divides the order of the group. Another method is to use the properties of conjugacy, where ord(yxy^-1) is equal to ord(x). Other methods may involve using the group's identity and inverse properties to manipulate the equations and show that they are equivalent.

Can you provide an example of a group where ord(x) = ord(yxy^-1) is shown?

One example is the group of integers modulo n, where n is a positive integer. In this group, if x and y are relatively prime to n, then ord(x) = ord(yxy^-1) = phi(n), where phi(n) is the Euler phi function. This can be proved using properties of modular arithmetic and Euler's theorem.

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