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In the equation x = x₀ + vt, 'x₀' means what?

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- Thread starter Indranil
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- #1

- 177

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In the equation x = x₀ + vt, 'x₀' means what?

- #2

russ_watters

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The subscript "0" pretty much always means the original/starting value.

- #3

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As I know x denotes 'displacement'. If x = 5 meters east, it means it's final position is 5 meters east but 'x₀' denotes what? is the object stationary in this case?The subscript "0" pretty much always means the original/starting value.

- #4

Drakkith

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In the equation x = x₀ + vt, 'x₀' means what?

It means the

As I know x denotes 'displacement'. If x = 5 meters east, it means it's final position is 5 meters east but 'x₀' denotes what? is the object stationary in this case?

If you write, ##x_0 = 5## then that would mean that the initial position of the object is, in a standard cartesian coordinate system (xy-plane), located at 5 units to the right of the origin.

- #5

lekh2003

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If ##x_0 = 5##, this means that the object in question starts out at 5 units in the positive direction (usually eastwards or to the right) from the origin (where x=0). This is the initial position.As I know x denotes 'displacement'. If x = 5 meters east, it means it's final position is 5 meters east but 'x₀' denotes what? is the object stationary in this case?

The ##x## value being spit out by the function gives you the final position of the object. This can be any new number.

However ##x## is not the displacement. The displacement would be ##\Delta x##, pronounced Delta ##x##. ##\Delta x## is the difference between ##x_0## and ##x##.

- #6

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Ok, then what would be the final position ( x ) from the concept above? what would be the final position value? I knew that the initial position is 0 and the final position is 5. Am I correct? Please explain.If ##x_0 = 5##, this means that the object in question starts out at 5 units in the positive direction (usually eastwards or to the right) from the origin (where x=0). This is the initial position.

The ##x## value being spit out by the function gives you the final position of the object. This can be any new number.

However ##x## is not the displacement. The displacement would be ##\Delta x##, pronounced Delta ##x##. ##\Delta x## is the difference between ##x_0## and ##x##.

Last edited:

- #7

Doc Al

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xIn the equation x = x₀ + vt, 'x₀' means what?

- #8

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Could you please provide me with a diagram so that I can clear my confusion? it's my humble request.x_{0}is the position at t = 0: the initial position.

- #9

Doc Al

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I'm not sure what sort of diagram you're looking for. The equation ##x = x_0 + vt## applies to constant velocity along a single axis (in this case the x axis). It gives you the final position along that axis after some time "t" passes. The final position depends on where you started (given by xCould you please provide me with a diagram so that I can clear my confusion? it's my humble request.

- #10

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Please provide me with any 'initial and final position' diagram. It would be very useful to me.I'm not sure what sort of diagram you're looking for. The equation ##x = x_0 + vt## applies to constant velocity along a single axis (in this case the x axis). It gives you the final position along that axis after some time "t" passes. The final position depends on where you started (given by x_{0}) and the distance you traveled in that time (given by vt).

- #11

jbriggs444

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Please provide me with any 'initial and final position' diagram. It would be very useful to me.

Code:

```
x axis: -----0--------x0-----------------------xf----
^ ^ ^
Origin Start here End here
```

- #12

Doc Al

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