- #1
jeremyfiennes
- 323
- 17
From a previous thread, Nugatory: "If the answers already supplied are not enough for the original poster to work out for themself why x=vt+x'/γ, and not x=vt+γx′, is the correct expression, we can have another thread devoted to only that question."
Here it is. Either Wiki is wrong or I am. In which case I need to know where my reasoning is faulty and why. My derivation:
– the frame A distance xa' of event X from the frame B origin is xa'=x-vt, Fig.(a)
– in frame B, everything stationary in frame A, including the distance xa', moves at speed v, and is therefore foreshortened by γ, Fig.(b)
– whence x' = xa'/γ = (x-vt)/γ, leading to x=vt+γx' as I maintain
– and not Wiki's x=vt+x/γ'
Here it is. Either Wiki is wrong or I am. In which case I need to know where my reasoning is faulty and why. My derivation:
– the frame A distance xa' of event X from the frame B origin is xa'=x-vt, Fig.(a)
– in frame B, everything stationary in frame A, including the distance xa', moves at speed v, and is therefore foreshortened by γ, Fig.(b)
– whence x' = xa'/γ = (x-vt)/γ, leading to x=vt+γx' as I maintain
– and not Wiki's x=vt+x/γ'